This is a common factor problem.
Pencils come in a pack of 12
Erasers come in a pack of 10
First, break the number into their prime factors(the idea is that we will break the number down into its smallest multiples, which are prime numbers):
10 = 2 * 5
12 = 2 * 2 *3
So now we take the unique multiples of each number, and when we multiply them together, we will get the smallest number that both 10 and 12 can be divided into(this is what the problem is asking for)
We have (2*2*3) that comes from 12, and the only unique number that comes from the 10 is (5)
So now, we multiply:
2*2*3*5=60
However, this isn't exactly out answer. Now we have to divide our answer by the number of each this in the pack to know how many packs to buy.
60/12=5 packs of pencils
60/10= 6 packs of erasers
I hope this helps. Let me know if you have any questions!!
The answer is 84 because of process priority
Answer:
Step-by-step explanation:
Answer:
79
Step-by-step explanation:
78
---------
7 | 62 03
49
----------
148 | 13 03
11 84
-----------
19
-----------
78^2 = 6084.
We observe that 78^2 < 6203.
79^2 = 6241.
We observe that 79^2 > 6203.
Hence the number to be added to 6203 is 6241 - 6203 = 38.
6203 + 38 = 3241
= 79 * 79
= 79.
Therefore 38 should be added to 6203 to obtain a perfect square.
