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soldi70 [24.7K]
3 years ago
15

Plsss I need help!!!

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
3 0

Answer:

POSSIBLY  2

Step-by-step explanation: wasnt the best at math but i hope u do good

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X^2 -5x + 7<br><br> If 1/3 x h(-8)
jeka94
The answer is 37!

(-8)^2 - 5(-8) + 7 = 111

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Can someone help me please?
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The answer is b bc the area of one cube is 57.76 so you multiply that by six bc there are six cubes. Once u do that you get 346.56 as the answer
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3 years ago
christian has $425.82 in his checking account . How much does he have in his account after he makes a deposit if 120.75 and with
Oksanka [162]
A deposit adds to the amount of a checking account.
So a deposit of $120.75 is + 120.75.
A withdraw subtracts from the amount of a checking account.
So a withdraw of $185.90 is - 185.90.

If the original amount is $425.82, you would simply add the amount of the deposit then subtract the amount of the withdraw.

425.82 + 120.75 - 185.90 = 360.67

So the amount in Christian's checking account after <span>a deposit if $120.75 and withdrawal of $185.90 is $360.67.

Answer:
$360.67

Hope this helps! :)
</span>
5 0
3 years ago
I need help for today :( plz
seropon [69]

Answer:

Step-by-step explanation:

Part C: (Explanation with steps)

Let the length of the swimming pool = l feet

And width of the pool = w feet

Perimeter of the pool = 2(l + w) feet

Since, perimeter of the pool = 8 feet

2(l + w) = 80

l + w = 40

l = (80 - w) -------(1)

Area of the pool = Length × width

A(w) = l × w

By substituting the value of l from equation (1)

A(w) = (80 - w) × w

A(w) = 80w - w²

To find the maximum area of the pool we will find the derivative of the function with respect to 'w' and equate it to zero.

A'(w) = 80 - 2w

(80 - 2w) = 0

w = \frac{80}{2}

w = 40 feet

Therefore, for width (w) = 40 feet area of the pool will be maximum.

From equation (1),

l = 80 - 40

l = 40 feet

Therefore, maximum area of the pool = l × w

                                                               = 40 × 40

                                                               = 1600 square feet

Part A:

Function representing area of the pool,

A(w) = -w² + 80w

Part B:

Maximum area of the surface of the pool = 1600 square feet

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<span>x + 3.75 
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