The amount of money that Davis has in this scenario is; $50
<h3>How to solve algebra word problems?</h3>
Let the amount of money he has be $X.
Now, if he buys 10 notebooks, he will have $10 left. Thus;
X - 10n = 10 -----(1)
If he buys 15 notebooks, he will be $10 short. Thus;
X - 15n = -10 ------(2)
Subtract eq 1 from eq 2 to get;
-5n = -20
n = -20/-5
n = 4
Thus;
X - 10(4) = 10
X = 10 + 40
n = $50
Read more about Algebra Word Problems at; brainly.com/question/21405634
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Answer:
54
Step-by-step explanation:
you could either add 125% and 24 to get 54
or you can figure out that 125% of 24 is 30 and add 24 and 30 together to get 54
Answer:
![\large\boxed{(f-g)(x)=-x^2+3x+7}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B%28f-g%29%28x%29%3D-x%5E2%2B3x%2B7%7D)
Step-by-step explanation:
![(f-g)(x)=f(x)-g(x)\\\\f(x)=3x+1,\ g(x)=x^2-6\\\\(f-g)(x)=(3x+1)-(x^2-6)=3x+1-x^2+6=-x^2+3x+7](https://tex.z-dn.net/?f=%28f-g%29%28x%29%3Df%28x%29-g%28x%29%5C%5C%5C%5Cf%28x%29%3D3x%2B1%2C%5C%20g%28x%29%3Dx%5E2-6%5C%5C%5C%5C%28f-g%29%28x%29%3D%283x%2B1%29-%28x%5E2-6%29%3D3x%2B1-x%5E2%2B6%3D-x%5E2%2B3x%2B7)
Hello,
Let's z=0.1234567891011121314151617181920.....(never end)
2/5=(2/(5z)*z<3241/1000 *z
3/4=(3/(4z))*z>6075/1000*z
So here is 2836 irrational numbers:
3241*z/1000
3242*z/1000
3243*z/1000
...
6073*z/1000
6074*z/1000
6075*z/1000
Answer:
a
Step-by-step explanation: