=Y2-10Y
We move all terms to the left:
-(Y2-10Y)=0
We add all the numbers together, and all the variables
-(+Y^2-10Y)=0
We get rid of parentheses
-Y^2+10Y=0
We add all the numbers together, and all the variables
-1Y^2+10Y=0
a = -1; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-1)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
Y1=−b−Δ√2aY2=−b+Δ√2a
Δ‾‾√=100‾‾‾‾√=10
Y1=−b−Δ√2a=−(10)−102∗−1=−20−2=+10
Y2=−b+Δ√2a=−(10)+102∗−1=0−2=0
Where a, b, and c are real numbers and a ≠ 0 .
The quadratic term is ax
2
, the linear term is
bx, and the constant term is c. Quadratic
functions have degree two. The graph of a
quadratic function is called a parabola. If
a < 0, then the parabola opens downward,
like function g. If
a > 0, then the parabola
opens upward like function f. If
the parabola opens upward, then
the vertex is the point whose yvalue
is the minimum value of f.
If the parabola opens downward,
then the vertex is the point
whose y-value is the maximum
value of f. The vertical line that
goes through the vertex is called
the axis of symmetry of the
parabola.
Answer:
The approximate probability is 0.7325.
Is not unlikely that a driver in that age bracket is involved in a car crash during a year, so there are reasons to be concerned.
Step-by-step explanation:
The approximate probability can be estimated using the sample proportion:
A probability of 0.7325 is high, so it is not unlikely that a driver in that age bracket is involved in a car crash during a year.
As this value is high, there is reasons to be concerned about it.
Answer:
−6.7 + (−2 1/ 5 )
Step-by-step explanation:
−6.7 + (−2 1/ 5 )
The area is 336 is you multiply the outer numbers then subtract the numbers on the in side that's what you get
