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creativ13 [48]
3 years ago
6

Plzzz answer !!!! Answer ASAP plz , would appreciate that

Mathematics
1 answer:
sertanlavr [38]3 years ago
4 0
38.7 feet per second
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Heights (in centimeters) and weights (in kilograms) of 7 supermodels are given below. Find the regression equation, letting the
Delvig [45]
The regression equation:
y = m x + b
m = ( 57 - 50 ) / ( 178 - 168 ) = 7 / 10 = 0.7
50 = 0.7 * 168 + b
50 = 117.6 + b
b = 50 - 117.6
b = - 67.6
y = 0.7 * x - 67.6
The graph is in the attachment.
The weight of supermodel who is 171 cm tall:
y = 0.7 * 171 - 67.6 = 119.7 - 67.6 = 52.1 kg
Download docx
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3 years ago
Can someone help me with #2 and #4
Juli2301 [7.4K]
A=4 X1.6hxhdhdhdhdhs
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Find two consecutive odd integers whose sum is 36.
miskamm [114]
2 consecutive odd integers...x and x + 2

x + (x + 2) = 36
2x + 2 = 36 <===
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4 years ago
Read 2 more answers
john receives a day worth of pay, p, for 4 days of newspaper delivery. He spent half of his money on gas. Then he spent 5$ on co
kirill [66]

Answer:

Let's assume John gets p for each day so his total is 4p. He spends half of that on gas, (4p)/2 = 2p. He has 2p left. Now subtract 5 from 2p for the coffee, and there is 35 left. So 2p - 5 = 35. Right? Now you can solve for p, by simplifying that equation.

Step-by-step explanation:

3 0
4 years ago
Can anyone help me solve this
yawa3891 [41]

Answer:

a. $45.54; b. $51.42; c. See below

Step-by-step explanation:

a. 193 min

        Service charge = $40.00

1st 100 min @ 0.021 =      2.10

Next 93 min @0.037 = <u>    3.44 </u>

                        Total =  $45.54

b. 317 min

          Service charge = $40.00

  1st 100 min @ 0.021 =      2.10

2nd 100 min @ 0.037 =     3.70

        117 min @ 0.048 =   <u>   5.62</u>

                          Total =   $51.42

c. Piecewise function

The charge is  

  • $40.00 + 0.021t               if t ≤ 100
  • $42.10 + 0.037(t - 100)    if 100 < t ≤ 200
  • $45.80 + 0.048 (t - 200) if t > 200

which we can write like this:

f(t) =\begin{cases}40.00 + 0.021t & t \leq 100\\42.10 + 0.037(t-100) & 100 < t \leq200\\45.80 + 0.048(t-200) & t > 200\end{cases}

5 0
3 years ago
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