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tiny-mole [99]
3 years ago
8

Pumpkin Weights (in lbs.)

Mathematics
2 answers:
RideAnS [48]3 years ago
8 0
The answer to the question is
a
levacccp [35]3 years ago
7 0

Answer:

<h2>(A). 30</h2>

Hope's its helps

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Priya has completed 9 exam questions. This is 60% of the questions on the exam. How many questions are on the exam?
USPshnik [31]

the whole exam will be 100%, and let's say that's "x" questions, but we also know that 9 is 60% of that so

\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 9&60 \end{array}\implies \cfrac{x}{9}=\cfrac{100}{60}\implies \cfrac{x}{9}=\cfrac{5}{3}\implies 3x=45 \\\\\\ x=\cfrac{45}{3}\implies x=15

8 0
3 years ago
lucas lives 5/8 mile from school.kenny lives twice as far as lucas from school.how many miles does kenny live from school
dexar [7]
<span><span>1.       </span>Lucas Lives 5/8 miles from their schools
=> 5/8 miles is equals to:
=> 5 / 8 = 0.625 miles.
Now, the problem says that Kenny lives twice as far as Lucas from their school.
Therefore, we only need to multiply the total number of miles of Lucas distance from house to school to be able to get what is the distance of Kenny’s house to school
=> 0.625 * 2 = 1.25 miles or 1 and ¼ miles.</span>



3 0
4 years ago
Solve the system of equations algebraically. Show all of your steps
Katyanochek1 [597]
I am going to explain this using the substitution method, considering it appears to be the best in this situation.

We know (from the bottom equation) that y can equal 3x+20. Using this knowledge, we substitute the y in the top equation for 3x+20. Now, we have an equation that looks like this:

3x+20=x^2+2x

Now we need to move x to one side and then do some radicals (square roots).
Subtract the 2x on the right (since it is smaller, negatives = NONONO), which will give you

x+20=x^2

Now, we take the square root of both sides to get

rad(x+20)=x

Now we have to simplify. 20 doesn't have a square root, but 4 goes into 20, and 4 has a square root of 2. This now becomes

2rad(x+5)

This doesn't simplify any further... we have a problem... no way to isolate x as far as my knowledge goes... Sorry, can't help you any further than that, but another person or your teacher might be able to. R.I.P...
4 0
3 years ago
An artist wants to frame a square painting with an area of 400 square inches if x is the length of the one side of the painting
tatuchka [14]

There is only one solution to the equation.  A quadratic equation has 2 solutions a positive and a negative, but since we are looking for length, the answer can only be postive.  Area= side^2

              400= x^2

         sqrt(400)=x

          20 inches = x  

The length of one side is 20 inches


check: 20*20 = 400, which is the area of the square painting.

8 0
3 years ago
How to solve -x^2-2x+1
Wittaler [7]

Answer:

Common factor

Factor by grouping

Factor by grouping

−

2

−

2

+

1

-x^{2}-2x+1

−x2−2x+1

−

1

(

2

+

2

−

1

)

{\color{#c92786}{-1(x^{2}+2x-1)}}

−1(x2+2x−1)

Solution−

-1(x²+ 2x-1 )

5 0
3 years ago
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