Disance between (x1,y1) and (x2,y2) is
![D= \sqrt{(x2-x1)^2+(y2-y1)^2}](https://tex.z-dn.net/?f=D%3D%20%5Csqrt%7B%28x2-x1%29%5E2%2B%28y2-y1%29%5E2%7D%20)
given (-2,5) (3,-4)
![D= \sqrt{(3-(-2))^2+(-4-5)^2}](https://tex.z-dn.net/?f=D%3D%20%5Csqrt%7B%283-%28-2%29%29%5E2%2B%28-4-5%29%5E2%7D%20)
![D= \sqrt{(5)^2+(-9)^2}](https://tex.z-dn.net/?f=D%3D%20%5Csqrt%7B%285%29%5E2%2B%28-9%29%5E2%7D%20)
![D= \sqrt{25+81}](https://tex.z-dn.net/?f=D%3D%20%5Csqrt%7B25%2B81%7D%20)
D=√106
the distance is √106 units or abotu 10.2
i can’t see it can you take a better picture
Answer:
y-intercept: 12
x-intercept: unknown
Step-by-step explanation:
I think you meant y=-32x+12.
Answer:
39
Step-by-step explanation:
i just did it on usa test prep