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Rudik [331]
3 years ago
10

Write as 73% decimal

Mathematics
2 answers:
pickupchik [31]3 years ago
7 0

.73 is your answer boo .

torisob [31]3 years ago
4 0
The answer is 0.73 becuase add a 100 to 73/100 then divide it to get 0.73
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2+x^2=18<br> Help please
Harlamova29_29 [7]

Answer:

2+x^2=18 = 2+4^2=18

Step-by-step explanation:

Because when you have the ( ^2) then that means your going to multiply a number by the same number and then 4 times 4 equals 16 and you still have the +2 therefore you add that on the 16 and 16+2 equals 18.

3 0
2 years ago
Solving Linear Equat<br> Solve the linear equation:<br> 3.4 + 2(9.7 – 4.8x) = 61.2
JulijaS [17]

Answer:

Step-by-step explanation:

Simplifying

3.4 + 2(9.7 + -4.8x) = 61.2

3.4 + (9.7 * 2 + -4.8x * 2) = 61.2

3.4 + (19.4 + -9.6x) = 61.2

Combine like terms: 3.4 + 19.4 = 22.8

22.8 + -9.6x = 61.2

Solving

22.8 + -9.6x = 61.2

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-22.8' to each side of the equation.

22.8 + -22.8 + -9.6x = 61.2 + -22.8

Combine like terms: 22.8 + -22.8 = 0.0

0.0 + -9.6x = 61.2 + -22.8

-9.6x = 61.2 + -22.8

Combine like terms: 61.2 + -22.8 = 38.4

-9.6x = 38.4

Divide each side by '-9.6'.

x = -4

Simplifying

x = -4

8 0
3 years ago
Read 2 more answers
HELP HELP I WILL GIVE ALL MY POINTS JUST HELP ME PLEASE
VladimirAG [237]

Answer:

A

Step-by-step explanation:

x = 0

y = -3

6 0
3 years ago
Read 2 more answers
List 3 values that would make this unequally true 48 &lt; 6n
charle [14.2K]
N> 8
Any value greater than 8 will work for n you choose

And this is why

48 < 6n
same thing as 
6n > 48
divide by 6 on both sides
And that leaves you with 
n>8

Examples which would work
n=9, n=120, n=756, n = 12
7 0
3 years ago
1. &amp; 2. In the diagram below, points A, B, and C are collinear. Answer each of the following questions. The figure shown bel
Lana71 [14]

Answer:

a)  \overline{AB} = 8 in

b) When the length of AC = 6\frac{1}{2} in. and BC = 3\frac{1}{2} in. \overline{AB} = 10 in

c)  When the length of AB = 10.2 in. and BC = 3.7 in.  \overline {AC}  = 6.5 in

d) When the length of AB =  4\frac{3}{4} in. and BC = 3\frac{1}{4} in. in. \overline {BC} =  1\frac{1}{2} in

Step-by-step explanation:

a) When the length of AC = 5 in. and CB = 3 in. we have;

The length of \overline {AB} = AC + CB (segment addition postulate)

Therefore;

\overline{AB} = 5 in. + 3 in. = 8 in.

b) When the length of AC = 6\frac{1}{2} in. and BC = 3\frac{1}{2} in. we have;

The length of \overline {AB} = AC + CB (segment addition postulate)

Therefore;

\overline{AB} = 6\frac{1}{2} in.+ 3\frac{1}{2} in. = 10 in.

c) When the length of AB = 10.2 in. and BC = 3.7 in. we have;

The length of \overline {AC} = AB - BC (converse of the segment addition postulate)

Therefore;

\overline {AC} = 10.2 in.+ 3.7 in. = 6.5 in.

d) When the length of AB =  4\frac{3}{4} in. and BC = 3\frac{1}{4} in. in. we have;

The length of \overline {BC} = AB - AC (converse of the segment addition postulate)

Therefore;

\overline {BC} = 4\frac{3}{4} in. -  3\frac{1}{4} in.=  1\frac{1}{2} in.

6 0
3 years ago
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