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frosja888 [35]
3 years ago
5

7. Explain the difference between an ionic compound and a molecule, on an atomic

Chemistry
1 answer:
galina1969 [7]3 years ago
3 0

Answer:

bakit Kay's lahat Ng module mahirap

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In which orbital does an electron in a bromine atom experience the greatest effective nuclear charge?
asambeis [7]

First let us determine the electronic configuration of Bromine (Br). This is written as:

Br = [Ar] 3d10 4s2 4p5

 

Then we must recall that the greatest effective nuclear charge (also referred to as shielding) greatly increases as distance of the orbital to the nucleus also increases. So therefore the electron in the farthest shell will experience the greatest nuclear charge hence the answer is:

<span>4p orbital</span>

4 0
4 years ago
Read 2 more answers
Which of these statements are true? Select all that apply.
777dan777 [17]

Answer:

The AH+ for Br2() is 0 kJ/mol.

The AH+ for Hg() is 0 kJ/mol.

The AH; for N261) is 0 kJ/mol.

Explanation:

7 0
3 years ago
What is the second hottest layer of the atmosphere?
kherson [118]
Well, I say the answer is Thermosphere! Hope I helped :) 
7 0
4 years ago
In the following reaction scheme, if the product D inhibits the activity of E, i is called E2E a. feedback control b, noncompeti
Alona [7]

Answer:

The correct option is : a. feedback control

Explanation:

Feedback inhibition is a type of enzyme inhibition and a cellular control mechanism. In this process the end product produced in an enzyme catalyzed reaction, binds and inhibits the activity of an enzyme. The first enzyme is generally inhibited, which in unique to a process. This inhibition involves the binding of the end-product on the allosteric site of the enzyme, which slows down or completely stops the reaction and the production of the product.

5 0
3 years ago
(b) Which solution has a higher percent ionization of the acid, a 0.10M solution of HC2H3O2(aq) or a 0.010M solution of HC2H3O2(
boyakko [2]

Answer: The percent ionization is higher for 0.010 M solution of HC_2H_3O_2

Explanation:

HC_2H_3O_2\rightarrow H^+C_2H_3O_2^-

 cM           0M           0M

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

a) Given c= 0.10 M and \alpha = ?

K_a=1.8\times 10^{-5}

Putting in the values we get:

1.8\times 10^{-5}=\frac{(0.10\times \alpha)^2}{(0.10-0.10\times \alpha)}

(\alpha)=0.013

\%(\alpha)=0.013\times 100=1.3\%

b) Given c= 0.010 M and \alpha = ?

K_a=1.8\times 10^{-5}

Putting in the values we get:

1.8\times 10^{-5}=\frac{(0.010\times \alpha)^2}{(0.010-0.010\times \alpha)}

(\alpha)=0.041

\%(\alpha)=0.041\times 100=4.1\%

The percent ionization is higher for 0.010 M solution of HC_2H_3O_2

6 0
3 years ago
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