Boyle's Law
Pressure 1 × Volume 1 = Pressure 2 × Volume2
or P1×V1= P2×V2
Finding Volume 2
(5.75atm)(5.14L) = (2.49atm)(V2)
Then Multiply
29.55atm•L = 2.49atm(V2)
Divided by 2.49
29.56atm•L / 2.49atm = 2.49atm(V2) / 2.49atm
V2= 11.87 L
The correct answer is B,
<span>It is endothermic, with both positive enthalpy and entropy changes.</span>
Answer: Concentration of N₂ is 4.8.
M.
Explanation:
is a constant of equilibrium and it is dependent of the concentrations of the reactants and the products of a balanced reaction. For
N2(g) + 2 O2(g) ⇄ 2 NO2(g)
= ![\frac{[NO2]^{2} }{[N2][O2]^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5BNO2%5D%5E%7B2%7D%20%7D%7B%5BN2%5D%5BO2%5D%5E%7B2%7D%20%7D)
From the question concentration of NO2 is twice of O2:
[NO2] = 2[O2]
Substituting this into
:
= ![\frac{[2O2]^{2} }{[N2][O2]^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5B2O2%5D%5E%7B2%7D%20%7D%7B%5BN2%5D%5BO2%5D%5E%7B2%7D%20%7D)
8.3.
= ![\frac{4O2^{2} }{[N2].O2^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7B4O2%5E%7B2%7D%20%7D%7B%5BN2%5D.O2%5E%7B2%7D%20%7D)
[N2] = 
[N2] = 
[N2] = 4.8.
The concentration of N2 in the equilibrium is [N2] = 4.8.
M.
The correct answer:C) NaCl(s)
Hope this helps!
Should be B, because one rotation is a day one revolution is a day(also to check I looked up the difference).