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Flura [38]
3 years ago
9

HELP QUITCKLY combine like terms to create an equivalent expression to 8(8+7J+8).

Mathematics
2 answers:
Elodia [21]3 years ago
6 0

Answer:

56J+128

Step-by-step explanation:

8(8+7J+8)

64+56J+64

56J+128

Zinaida [17]3 years ago
3 0

Answer: 56j + 128

Step-by-step explanation:

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given the side lengths of 6, 13, and 20, determine whether the triangle is acute , right , obtuse, or not a triangle.
Serggg [28]

Answer:

Not a triangle.

Step-by-step explanation:

Sum of the two smaller sides must be greater than the largest side.

8 0
3 years ago
A credit card bill is best kept in which of the following places?
Minchanka [31]

Answer: SAFE DEPOSITE BOX

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is the value of 3-6(z-2) if z=-2
krek1111 [17]

Answer:

27

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

3 - 6(z - 2)

z = -2

<u>Step 2: Evaluate</u>

  1. Substitute in <em>z</em>:                   3 - 6(-2 - 2)
  2. (Parenthesis) Subtract:      3 - 6(-4)
  3. Multiply:                              3 + 24
  4. Add:                                    27
6 0
3 years ago
Read 2 more answers
The altitude of a triangle is increasing at a rate of 1 cm/min while the area of the triangle is increasing at a rate of 2 cm^2/
VARVARA [1.3K]

Answer:

The base is decreasing at 2 cm/min.

Step-by-step explanation:

The area (A) of a triangle is given by:

A = \frac{1}{2}bh   (1)

Where:

b: is the base

h: is the altitude = 10 cm

If we take the derivative of equation (1) as a function of time we have:

\frac{dA}{dt} = \frac{1}{2}(\frac{db}{dt}h + \frac{dh}{dt}b)

We can find the base by solving equation (1) for b:

b = \frac{2A}{h} = \frac{2*120 cm^{2}}{10 cm} = 24 cm

Now, having that dh/dt = 1 cm/min, dA/dt = 2 cm²/min we can find db/dt:

2 cm^{2}/min = \frac{1}{2}(\frac{db}{dt}*10 cm + 1 cm/min*24 cm)

\frac{db}{dt} = \frac{2*2 cm^{2}/min - 1 cm/min*24 cm}{10 cm} = -2 cm/min    

         

Therefore, the base is decreasing at 2 cm/min.

               

I hope it helps you!  

7 0
2 years ago
I already solved this problem. I just need help with the HINT part.
frutty [35]
x+y=25 \\ y=25-x~~Other~number~in~terms~of~x \\ \\ x^2+y^2=313 \\ x^2+2xy+y^2=313+2xy \\ (x+y)^2=313+2x(25-x) \\ \frac{25^2-313}{2} =25x-x^2 \\ x^2-25x+156 \\ \\ \Delta =(-25)^2-4\times 1\times 156 \\ \Delta =625-624 \\ \sqrt{\Delta}=1 \\ \\ x= \frac{25 \pm 1}{2} \\ x= \left \{ {{x_1=13} \atop {x_2=12}} \right.

     The number "x" is given by:
y= \left \{ {{y_1=25-13 \rightarrow~y_1=12} \atop {y_1=25-12 \rightarrow ~y_1=13}} \right.
  
     Therefore, we have:

\boxed {S=({12,13})} \rightarrow~The~curly~braces~does~not~want~appear~here.
8 0
3 years ago
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