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allsm [11]
2 years ago
7

The graphs show the distances traveled by two cars moving at constant rates.

Mathematics
1 answer:
icang [17]2 years ago
4 0

Answer:

67

Step-by-step explanation:

only a guess

distances traveled by two cars moving at constant rates

You might be interested in
(easy)
Andreyy89

Answer:

<h2>9 weeks</h2>

Step-by-step explanation:

Sol had $1535 in his savings

has been spending $30 each week for guitar lessons.

If his current balance is $1265

find:

how many weeks has he been taking lessons?

$1535 - $1265 = $270

<u>            $270      </u>  =  9 weeks

$ 30 per week

7 0
3 years ago
Ecuación 2:<br> 10x + 20y = 8000<br> ayudaaa
Elenna [48]

Answer:

y = 300

x = 200

Step-by-step explanation:

Esta pregunta parece incompleta, parece que acá tenemos un sistema de ecuaciones:

x + y = 500

10*x + 20*y = 8000

Estas ecuaciones tienen que resolverse en conjunto, y de acá sacaremos un par de puntos (x, y) que son solución para ambas ecuaciones.

El primer paso para resolver esto es aislar una variable en una de las ecuaciones, en este caso podemos aislar x en la primera ecuación y así obtener:

x = 500 - y.

Ahora podemos reemplazar eso en la segunda ecuación y obtener:

10*(500 - y) + 20*y = 8000.

Ahora resolvemos esto para y.

5000 - 10*y + 20*y = 8000

10*y = 8000 - 5000 = 3000

y = 3000/10 = 300.

Y sabíamos que:

x = 500 - y = 500 - 300 = 200

Entonces la solución es:

y = 300

x = 200

4 0
3 years ago
What is the equation of the line shown in this graph
prisoha [69]
Slope = (2+4)/(1-4) = 6/-3 = -2
passing thru (1.2)
y = mx + b
b = y - mx
b = 2 - (-2)(1)
b = 2 + 2
b = 4

equation
y = -2x + 4
7 0
2 years ago
NEED HELP HERE ASAP<br><br> 6. Find the cube roots of 27(cos 330° + i sin 330°).
VLD [36.1K]
<span>we have that

the cube roots of 27(cos 330° + i sin 330°) will be
</span>∛[27(cos 330° + i sin 330°)]

we know that
e<span>^(ix)=cos x + isinx
therefore
</span>∛[27(cos 330° + i sin 330°)]------> ∛[27(e^(i330°))]-----> 3∛[(e^(i110°)³)]
3∛[(e^(i110°)³)]--------> 3e^(i110°)-------------> 3[cos 110° + i sin 110°]

z1=3[cos 110° + i sin 110°]

 cube root in complex number, divide angle by 3
360nº/3 = 120nº --> add 120º for z2 angle, again for z3
<span>therefore
</span>
z2=3[cos ((110°+120°) + i sin (110°+120°)]------ > 3[cos 230° + i sin 230°]

z3=3[cos (230°+120°) + i sin (230°+120°)]--------> 3[cos 350° + i sin 350°]
<span>
the answer is 

</span>z1=3[cos 110° + i sin 110°]<span>

</span>z2=3[cos 230° + i sin 230°]

z3=3[cos 350° + i sin 350°]<span>

</span>
7 0
3 years ago
A city planner is mapping out some new features for a triangle park. She sketches the park on a grid paper. The coordinates of t
Alecsey [184]

Answer:

Perhaps, she is interested in finding the area enclosed by this triangular park.

Step-by-step explanation:

The area of the triangle enclosed by the three points

A(1,1), B(1,4) and C(-3,4) in this question will be given by

|Ax ( By  − Cy)+ Bx(Cy−Ay)+ Cx(Ay− By) |/2  

=|1(4-4)+1(4-1)+-3(1-4)|/2=10/5= 5 sq. units.

5 0
3 years ago
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