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vesna_86 [32]
3 years ago
10

An object which is dropped from a certain height has zero (0) initial velocity.

Physics
1 answer:
gavmur [86]3 years ago
8 0

Answer:

0 m/s

Explanation:

if an object is dropped we know the initial velocity is zero when in free fall

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The energy stored in compounds and released in reactions is what kind of energy?
Lubov Fominskaja [6]

The answer is D. Chemical Energy

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Magnetism/ magnetic field ana magnetic forces
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Magnetism is a physical phenomenon that manifests itself in a force acting between magnets or other magnetized or magnetisable objects, and a force acting on moving electric charges, such as in current-carrying cables. The force action takes place by means of a magnetic field, which is generated by the objects themselves or otherwise. There are natural and artificial magnets. All magnets have two poles called the north pole and the south pole. The north pole of one magnet repels the north pole of another magnet and attracts the south pole of another magnet; the same with south poles.  

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PLS HELP!!! David looks up at the sky several times one night. He notices that the stars appear to move across the sky. Why do t
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b

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5 0
3 years ago
Marisol is designing a system to detect when the door to her room is opened. She has observed that the magnetic field in the vic
KIM [24]

Answer:

The minimum time interval required is 18.1 sec

Explanation:

Given:

Magnetic field B = 5.50 \times 10^{-5} T

Minimum induced emf \epsilon = 1 \times 10^{-6} V

Angle between magnetic field and area vector \theta = 34°

Area of door A = 0.895 \times 2.15 = 1.924 m^{2}

According to the faraday's law,

   \epsilon = -\frac{d\phi}{dt}

Where \phi = magnetic flux

From the formula of magnetic flux,

  \phi = BA\cos \theta

Initially,

  \phi _{i} = BA\cos 34

      = 5.50 \times 10^{-5} \times 1.924 \times 0.8290

      = 8.773 \times 10^{-5} Wb

When door is closed,

 \phi _{f} = BA\cos 0

      = 5.50 \times 10^{-5} \times 1.924

 \phi _{f} = 10.58 \times 10^{-5} Wb

Hence d\phi = \phi _{f} - \phi _{i}

 d\phi = (10.58 - 8.773 ) \times 10^{-5}

 d \phi = 1.81 \times 10^{-5} Wb

Put the values in above equation,

  dt = \frac{d \phi}{\epsilon}

  dt = \frac{1.81 \times 10^{-5} }{1 \times 10^{-6} }

  dt = 18.1 sec

Therefore, the minimum time interval required is 18.1 sec

6 0
3 years ago
What is the initial velocity of a go-kart traveling at a uniform acceleration of 0.5 m/s^2 for 5s as it slows down to a stop?
Arlecino [84]

The go-kart's velocity v after time t is given by

v=v_0+at

where v_0 is its initial velocity and a is its acceleration. After t=5\,\mathrm s, the go-kart stops completely, so

0\,\dfrac{\mathrm m}{\mathrm s}=v_0+\left(-0.5\,\dfrac{\mathrm m}{\mathrm s^2}\right)(5\,\mathrm s)\implies v_0=2.5\,\dfrac{\mathrm m}{\mathrm s}

where a because we know the go-kart is slowing down.

7 0
4 years ago
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