Answer:
The maximum energy that can be stored in the capacitor is 6.62 x 10⁻⁵ J
Explanation:
Given that,
dielectric constant k = 5.5
the area of each plate, A = 0.034 m²
separating distance, d = 2.0 mm = 2 x 10⁻³ m
magnitude of the electric field = 200 kN/C
Capacitance of the capacitor is calculated as follows;

Maximum potential difference:
V = E x d
V = 200000 x 2 x 10⁻³ = 400 V
Maximum energy that can be stored in the capacitor:
E = ¹/₂CV²
E = ¹/₂ x 8.275 x 10⁻¹⁰ x (400)²
E = 6.62 x 10⁻⁵ J
Therefore, the maximum energy that can be stored in the capacitor is 6.62 x 10⁻⁵ J
Answer:
id say D
Explanation:
because its the only answer that has to do with colors and visable light
but A and B also have to do with eachother so i feel like it could be with one of those but it def isnt C
I am sorry if i am wrong, let me know tho!
Answer:
500 kW
Explanation:
Given that,
Energy of the train, E = 2 MJ = 2×10⁶ J
Time, t = 4 seconds
We need to find the power of the train. We know that,
Power = energy/time
So,

So, the power of the train is equal to 500 kW.