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Kryger [21]
4 years ago
8

What is the initial velocity of a go-kart traveling at a uniform acceleration of 0.5 m/s^2 for 5s as it slows down to a stop?

Physics
1 answer:
Arlecino [84]4 years ago
7 0

The go-kart's velocity v after time t is given by

v=v_0+at

where v_0 is its initial velocity and a is its acceleration. After t=5\,\mathrm s, the go-kart stops completely, so

0\,\dfrac{\mathrm m}{\mathrm s}=v_0+\left(-0.5\,\dfrac{\mathrm m}{\mathrm s^2}\right)(5\,\mathrm s)\implies v_0=2.5\,\dfrac{\mathrm m}{\mathrm s}

where a because we know the go-kart is slowing down.

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Answer:

(d) I and III

Explanation:

Motion of the 1st  light ball

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I. Since the heavier starts with an initial velocity v0, and both balls end up traveling the same distance s. From the 2 motion equation above we can conclude that their time must be different

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III. Velocity before the impact of the light ball

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And the heavy ball

v_2^2 - v_0^2 = 2gs

Since they have the same acceleration g and distance s. But the heavy ball has an initial push. It would end up with a larger speed.

7 0
3 years ago
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Alexxandr [17]

The ice melts because Thermal energy from Jan’s hand is transferred to the ice.

<h3>What is thermal energy?</h3>

Thermal energy is the energy due to temperature difference.

Thermal energy flows from hotter to colder bodies.

The ice Jan is holding melts because heat is transferred from his hands t the ice.

In conclusion, thermal energy flow causes melting.

Learn more about thermal energy at: brainly.com/question/19666326

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3 0
2 years ago
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