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Kryger [21]
3 years ago
8

What is the initial velocity of a go-kart traveling at a uniform acceleration of 0.5 m/s^2 for 5s as it slows down to a stop?

Physics
1 answer:
Arlecino [84]3 years ago
7 0

The go-kart's velocity v after time t is given by

v=v_0+at

where v_0 is its initial velocity and a is its acceleration. After t=5\,\mathrm s, the go-kart stops completely, so

0\,\dfrac{\mathrm m}{\mathrm s}=v_0+\left(-0.5\,\dfrac{\mathrm m}{\mathrm s^2}\right)(5\,\mathrm s)\implies v_0=2.5\,\dfrac{\mathrm m}{\mathrm s}

where a because we know the go-kart is slowing down.

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If we are viewing the atom in such a way that the electron's orbit is in the plane of the paper with the electron moving clockwi
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Answer:

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Explanation:

Given:

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For finding the magnitude of the electric field,

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Where k = 9 \times 10^{9}

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Therefore, the magnitude  of the electric field is 5.1 \times 10^{11}  \frac{N}{C}

5 0
4 years ago
What would you do if natural calamity or disaster strikes you now ?
il63 [147K]

Answer:

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Explanation:

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5 0
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6 0
3 years ago
Read 2 more answers
A sinusoidal wave on a string is described by the wave function
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<h3>Wave function</h3>

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Learn more on speed of the wave here: brainly.com/question/25847009

#SPJ4

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2 years ago
Liquid nitrogen boils at 77.2 k. what is this temperature in degrees celsius
Ratling [72]
<span>77.2 k is -195.95 C
       
To convert from Kelvin to Celsius, you simply subtract 273.15 from the temperature. So the expression becomes c = 77.2 - 273.15 = -195.95</span>
6 0
3 years ago
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