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Kryger [21]
3 years ago
8

What is the initial velocity of a go-kart traveling at a uniform acceleration of 0.5 m/s^2 for 5s as it slows down to a stop?

Physics
1 answer:
Arlecino [84]3 years ago
7 0

The go-kart's velocity v after time t is given by

v=v_0+at

where v_0 is its initial velocity and a is its acceleration. After t=5\,\mathrm s, the go-kart stops completely, so

0\,\dfrac{\mathrm m}{\mathrm s}=v_0+\left(-0.5\,\dfrac{\mathrm m}{\mathrm s^2}\right)(5\,\mathrm s)\implies v_0=2.5\,\dfrac{\mathrm m}{\mathrm s}

where a because we know the go-kart is slowing down.

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2. A 55 kg woman has a momentum of 200 kg m/s. What is her velocity?
NeTakaya

Answer:

\boxed {\tt 3.63636364 \ m/s}

Explanation:

Velocity can be found using the following formula:

v=\frac{p}{m}

where p is the momentum and m is the mass.

The woman has a mass of 55 kilograms and a momentum of 200 kilogram meters per second.

p= 200 \ kgm/s\\m=55 \ kg

Substitute the values into the formula.

v=\frac{200 \ kg m/s}{55 \ kg}

Divide. Note that the kilograms, or kg, will cancel each other out.

v=\frac{200 \ m/s}{55}

v= 3.63636364 \ m/s

The woman's velocity is 3.63636364 meters per second.

6 0
3 years ago
How do you know that a chemical change has happened
Elodia [21]

Answer:

theres is many states of chemical change but its not exaclty the same as physical the appearence might change alittle but chemical like frying a egg is a chemical change because a change of materials into another, new materials with different properties and one or more than one new substances are formed and the subtance changeing or the materials can show chemical changed happened you cant always see it but touching too like heat energy can show a chemical change

Explanation:

i hope this helps and keep ur grades up :)

6 0
1 year ago
Read 2 more answers
Weight=1500n area=0.5 m2 pressure=​
Dmitriy789 [7]

Answer: 6000N/m^2

Explanation:

Weight =1500N

Area =0.5m^2

Pressure =1500/(0.5^2)

               =6000N/m^2

Note: Newton is denoted by 'N' (Capital) and use '^' for powers.

8 0
2 years ago
Before beginning a long trip on a hot day, a driver inflates anautomobile tire to a gauge pressure of 2.70 atm at 300 K. At the
anygoal [31]

Answer:

The value is the temperature of the air inside the tire T_{2} = 340.54 K

% of the original mass of air in the tire should be released 99.706 %

Explanation:

Initial gauge pressure = 2.7 atm

Absolute pressure at inlet P_{1} = 2.7 + 1 = 3.7 atm

Absolute pressure at outlet P_{2} = 3.2 + 1 = 4.2 atm

Temperature at inlet T_{1} = 300 K

(a) Volume of the system is constant so  pressure is directly proportional to the temperature.

\frac{T_{2} }{T_{1} } = \frac{P_{2} }{P_{1} }

\frac{T_{2} }{300}  = \frac{4.2}{3.7}

T_{2} = 340.54 K

This is the value is the temperature of the air inside the tire

(b). Since volume of the tyre is constant & pressure reaches the original value.

From ideal gas equation P V = m R T

Since P , V & R is constant. So

m T = constant

m_{1}  T_{1} =  m_{2}  T_{2}

\frac{m_{2} }{m_{1}  } = \frac{T_{1} }{T_{2} }

\frac{m_{2} }{m_{1}  } = \frac{300}{354.54}

\frac{m_{2} }{m_{1}  } =0.00294

value of  the original mass of air in the tire should be released is  \frac{m_{2} - m_{1}}{m_{1}}

\frac{0.00294-1}{1}

⇒ -0.99706

% of the original mass of air in the tire should be released 99.706 %.

8 0
2 years ago
How do I set up this equation?
Natalka [10]
They start at 1 meter and after 10 seconds they've moved to 6 meters.
 6 - 1 = 5 meters
4 0
3 years ago
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