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Tems11 [23]
3 years ago
13

What most closley defines population density?

Physics
1 answer:
Genrish500 [490]3 years ago
3 0
The carrying capacity of a biological species in an environment is the maximum population size of the species that the environment can sustain indefinitely, given the food, habitat, water, and other necessities available in the environment.
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Help me slove this problem 115 divided by 2
zhenek [66]
115 divided by 2 equals 57.5
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How you can change the state of matter of the substance in the container.
Deffense [45]

Answer:

Change in the shape size volume and state of a substance

When a solid is heated, it turns into a liquid. As a liquid, a substance has a fixed volume, but its shape changes to fill the shape of its container. For instance, a glass of water is the liquid state of water. ... Gas expands to fill the shape and volume of its container.

Explanation:

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Which of the following are early clues that signal an earthquake may occur? Select all that apply. Changes in magnetic propertie
enot [183]

The following answers apply;

  • Changes in magnetic properties of rock
  • Decrease in well water levels
  • Increases in radon gas in groundwater
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These other choices may be good indicators of an imminent volcanic eruption;

Movement of magma

Increase in sulfur dioxide and carbon dioxide ground emissions


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Which vector below goes from (0,0) to (1,-3)?
vitfil [10]

I think D. It starts at (0.0) and goes to the correct points so it makes sense

8 0
3 years ago
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A disk of mass M and radius R rotates at angular velocity ω0. Another disk of mass M and radius r is dropped on top of the rotat
AleksandrR [38]

Answer:

\omega = \frac{(R^2\omega_o}{(R^2 + r^2)}

Explanation:

As we know that there is no external torque on the system of two disc

then the angular momentum of the system will remains conserved

So we will have

L_i = L_f

now we have

L_i = (\frac{1}{2}MR^2)\omega_o

also we have

L_f = (\frac{1}{2}MR^2 + \frac{1}{2}Mr^2)\omega

now from above equation we have

(\frac{1}{2}MR^2)\omega_o  = (\frac{1}{2}MR^2 + \frac{1}{2}Mr^2)\omega

now we have

\omega = \frac{MR^2\omega_o}{(MR^2 + Mr^2)}

\omega = \frac{(R^2\omega_o}{(R^2 + r^2)}

6 0
3 years ago
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