Answer:
2<em>x</em>^2+7<em>x</em>+6
Step-by-step explanation:
Expand the polynomial (An algebraic expression) using the FOIL (First, Outer, Inner, Last) method.
2<em>x</em>^2+7<em>x</em>+6
(<em>x</em>+2)(2<em>x</em>+3)
First, <em>multiply the variables</em> (<em>x</em>).
(<em>x</em>)(2<em>x</em>) = 2<em>x</em>^2
- <em>NOTE: the '^' before a number is used to signify an exponent.</em>
Then, <em>multiply the whole numbers</em> (2, 3).
(2)(3) = 6
Now, you're not done. You need to <em>multiply the variables and the whole numbers </em>(that weren't already multiplied together)
(<em>x</em>)(3) = 3<em>x</em>
(2)(2<em>x</em>) = 4<em>x</em>
- <em>NOTE: make sure you're multiplying one expression to the other, </em><em>not </em><em>multiplying the same expression together.</em>
Finally, add them all together, and simplify.
2<em>x</em>^2 + 6 +3<em>x </em>+ 4<em>x</em>
<em>=</em>
2<em>x</em>^2+7<em>x</em>+6