Answer:
-2
Step-by-step explanation:
Linear equations are typically organized in slope-intercept form:
where m is the slope and b is the y-intercept (the value of y when the line crosses the y-axis). To solve this question, first, find the slope, then, plug one of the given points into the equation to isolate b.
<u>1) Find the slope (m)</u>
where the given points are
and ![(x_2,y_2)](https://tex.z-dn.net/?f=%28x_2%2Cy_2%29)
Plug in the given points (0,-2) and (3,0)
![m=\frac{0-(-2)}{3-0}\\m=\frac{0+2}{3}\\m=\frac{2}{3}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B0-%28-2%29%7D%7B3-0%7D%5C%5Cm%3D%5Cfrac%7B0%2B2%7D%7B3%7D%5C%5Cm%3D%5Cfrac%7B2%7D%7B3%7D)
Therefore, the slope of of the line is
. Plug this into
as m:
![y=\frac{2}{3} x+b](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%7D%7B3%7D%20x%2Bb)
<u>2) Find the y-intercept (b)</u>
![y=\frac{2}{3} x+b](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B2%7D%7B3%7D%20x%2Bb)
Plug in one of the given points: (0,-2) or (3,0)
![0=\frac{2}{3} (3)+b\\0=2+b\\b=-2](https://tex.z-dn.net/?f=0%3D%5Cfrac%7B2%7D%7B3%7D%20%283%29%2Bb%5C%5C0%3D2%2Bb%5C%5Cb%3D-2)
Therefore, the y-intercept of the line AB is -2.
I hope this helps!