The first tank contains
486 gal - (4 gal/week) <em>t</em>
gal of water after <em>t</em> weeks.
Similarly, the second tank contains
648 gal - (7 gal/week) <em>t</em>
gal of water.
The tanks hold the same amount of water when these two amounts are equal:
486 gal - (4 gal/week) <em>t</em> = 648 gal - (7 gal/week) <em>t</em>
(7 gal/week) <em>t</em> - (4 gal/week) <em>t</em> = 648 gal - 486 gal
(3 gal/week) <em>t</em> = 162 gal
<em>t</em> = (162 gal) / (3 gal/week)
<em>t</em> = 54 weeks
Answer:
its c
Step-by-step explanation:
Answer:
y=6x
Step-by-step explanation:
Each value for y is can be divided by 6 for the value of x
<span>{x | x < 0} and {x | x > 0}</span>
I believe the correct answer is true. <span>When solving a system of linear equations, try to algebraically form one equation that has only one variable. In this way, you can solve the value of that variable and eventually solve the other variables. Hope this answers the question. Have a nice day.</span>
