1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NNADVOKAT [17]
3 years ago
14

Solve x – 2y = 12 if the domain is {–3, –1, 0, 2, 5}.

Mathematics
2 answers:
serg [7]3 years ago
8 0

Answer:

Step-by-step explanation:

konstantin123 [22]3 years ago
8 0

Answer:

answer is below

Step-by-step explanation:

x - 2y = 12

<em><u>First step is to solve for y, so</u></em>

<em><u></u></em>x - 2y = 12

<em><u>Then, subtract x on both sides to isolate the variable, y. </u></em>

<em><u></u></em>-2y = -x + 12

<em><u>Divide both sides by -2</u></em>

<em><u></u></em>y = \frac{1}{2}x - 6

------------------------------------------------------------------------------------------------------

<em><u>The domain is</u></em> {-3,-1,0,2,5}

Domain is the set of x values

Range is the set of y values

We are given the domain x, we need to find out the y values using the equation: y= \frac{1}{2}x - 6

y = \frac{1}{2}(-3) -6 = \frac{-15}{2} = -7.5\\\\y = \frac{1}{2}(-1) -6 = \frac{-13}{2} = -6.5\\\\y = \frac{1}{2}(0) -6 = -6\\\\y = \frac{1}{2}(2) -6 = -5\\\\\\y = \frac{1}{2}(5) -6 = -\frac{7}{2} = - 3.5

<em><u>therefore,</u></em>

when x is -3: y = -7.5

when x is -1: y = -6.5

when x is 0: y = -6

when x is 2: y = -5

when x is 5: y = -3.5

Range is {-7.5, -6.5, -6 , -5, -3.5}

hope this helps and is right :)

p.s. i really need brainliest

You might be interested in
Can someone explain how to do this please?
Rufina [12.5K]

for the columns where is less than or equal zero, use the first line of the function to calculate the value of f(x)

{ ( \frac{1}{3} ) }^{ - 2} - 1  = 9 - 1 = 8 \\ { ( \frac{1}{3} ) }^{ - 1}  - 1 = 3 - 1 = 2 \\ { ( \frac{1}{3} ) }^{ 0} - 1  = 1 - 1 = 0

for every x greater than zero, use the second line to determine the value

{3}^{1}  - 2 = 3 - 2 = 1 \\ {3}^{2}  - 2 = 9 - 2 = 7

hope this helps and gives some insight what to do.

if there are open questions left, feel free to ask them in the comments

have a beautiful day

-Alex

3 0
3 years ago
Graph the image of this quadrilateral after a dilation with a scale factor of 4 centered at the origin
Brut [27]

Answer: The image is attached.

Step-by-step explanation:

A Dilation is defined as  a transformation in which the image and the pre-image have the same shape, but their sizes are different.

When the scale factor is greater than 1, the image obtained after the  dilation is greater than the pre-image and it is an "Enlargement".

When the scale factor is is between 0 and 1,  the image obtained after the  dilation is smaller than the pre-image and it is an "Reduction".

In this case we know that the scale factor is:

scale\ factor=4

Since:

4>1

It is an Enlargement.

You can identify that the vertices of the pre-image shown in the figure, are:

(-2,1)\\\\(-1,2)\\\\(0,0)\\\\(-1,-2)

So you need to multiply the coordinates of those vertices by 4 in order to get the coordinates of the image;

((-2)(4),1(4))=(-8,4)\\\\((-1)(4),(2)(4))=(-4,8)\\\\((0)(4),(0)(4)=(0,0)\\\\((-1)(4),(-2)(4))=(-4,-8)

Now you can draw it (The image is attached).

8 0
3 years ago
Theo has a balence of $-4 in his savings account. After making a deposit, he has $25 in his account.What is the overall change t
lions [1.4K]

The has a +$29 change in his account

6 0
3 years ago
Read 2 more answers
3x-1upon5 =x-1upon3<br> Solution for this linear equation
BabaBlast [244]

The solution to the linear equation is 2

<h3>How to solve the linear equation?</h3>

The linear equation is given as:

3x - 1 upon 5 = x - 1 upon 3

Rewrite properly as

(3x - 1)/5 = (x - 1)/3

Cross multiply

9x - 3 = 5x- 5

Evaluate the like terms

4x = 8

Divide by 4

x = 2

Hence, the solution to the linear equation is 2

Read more about linear equations at:

brainly.com/question/14323743

#SPJ1

7 0
1 year ago
Find the area of the figure.
ipn [44]

Answer:

89m

Step-by-step explanation:

First, find the area of the rectangle (ignoring the missing triangle inside). The area of the rectangle is its base times its height, which is 8*13=104.

Next, find the area of the triangle. The area of the triangle is its base times height, divided by two.

The width of one side of the rectangle is 13, and the width of the side of the rectangle is 8 (4 + 4). Therefore, subtract 8 from 13 and the missing section in the side of the rectangle is 5. 5 is equal to the base of the triangle.

The height of the triangle is given, which is 6. As stated before, the area of a triangle is its base times height divided by two, which is 5*6/2 in this case. The area of the triangle is equal to 15.

Now, subtract the area of the triangle from the area of the rectangle. 104-15=89.

3 0
4 years ago
Other questions:
  • Can someone please help me with this surface area of cylinder problem. I thought I had it but I didn't, I've gotten help from my
    11·1 answer
  • Ebru has a standard deck of cards. The deck has 52 total cards and contains 4 suits: hearts, clubs, diamonds, and
    14·1 answer
  • Is a directed segment with endpoints A(2,2) and B(14,14). In two or more complete sentences, explain how you would verify that P
    5·2 answers
  • Geometry math problem
    11·2 answers
  • Mary having her living room and bedroom painted. Interior Designs USA charges $60.00 to evaluate the space plus $35.00 per hour
    15·1 answer
  • A dvd is marked down 15% the regular price is $12 what is the sale price?
    5·2 answers
  • The element bromine exists in nature as two isotopes: 79Br has a mass of 78.9183 u, and 81Br has a mass of 80.9163 u. The averag
    10·1 answer
  • What is the x-intercept of the graph 0f 27= -3x2?
    8·1 answer
  • Please tell me which ones I should select!!
    15·1 answer
  • Use the quadratic formula to find both solutions to the quadratic equation
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!