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Shkiper50 [21]
3 years ago
12

What is simple harmonic motion give two examples

Physics
2 answers:
lord [1]3 years ago
8 0
Ex1- Swing

Swings that we see in the park is an example of simple harmonic motion

Ex2- Hearing

The process of hearing is is impossible without simple harmonic motion. The sound waves that enter our ear causes the eardrum to vibrate back and forth

Bonus Ex- cradle

The back and forth movement of the cradle caused due to a single push and is maintained by the principle of SHM, and hence, caused the baby to sleep.

Hope it helps
Reil [10]3 years ago
7 0

Answer:

S.H.M:- If the acceleration of the vibrating body directly varies with the displacement of the body from the mean position and always directed to the mean position, the motion of that body is called simple harmonic motion.

Ex:- (i) The motion of a pendulum is an S.H.M.

(ii) The motion of vibrating mass attached to a spring is an S.H.M.

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When a 2.60-kg object is hung vertically on a certain light spring described by Hooke's law, the spring stretches 2.86 cm. (a) W
Goryan [66]

Answer:

a)  k = 891.82 N/m

b) e = 0.0143 m = 1.43 cm

c) W = 5.02 J

Explanation:

Step 1: Data given

Mass = 2.60 kg

the spring stretches 2.86 cm = 0.0286

Step 2: What is the force constant of the spring?

Force constant, k = force applied / extension produced  

k = (2.60kg * 9.81N/kg) / 0.0326 m

k = 891.82 N/m

b)  If the 2.60-kg object is removed, how far will the spring stretch if a 1.30-kg block is hung on it

Extension = F/k = (1.30 kg * 9.81) / 891.82 =  0.0143 m = 1.43 cm

Half the mass means half the extension

c) How much work must an external agent do to stretch the same spring 7.50 cm from its unstretched position?

W = average force used * distance

W = 1/2 * k*e * e = 1/2 k*e²  

W = 1/2 * 891.82 * (0.075)² = W = 5.02 J

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3 years ago
In electric motors and electric generators, which part is responsible for transferring current from the power source to the comm
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The BRUSH <span>In electric motors and electric generators is responsible for transferring current from the power source to the commutator or from the slip rings to where the electricity is needed</span>
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4 years ago
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3 points
blagie [28]

Answer:

A and D

Explanation:

Acceleration is the active change in speed, increasing or decreasing.

8 0
3 years ago
Two capacitors, C1 = 25.0 μF and C2 = 31.0 μF, are connected in series, and a 6.0-V battery is connected across them.a. Find the
Brrunno [24]

Answer:

13.83928\times 10^{-6}\ F

249.10704\times 10^{-6}\ J

137.89848\times 10^{-6}\ J

111.20842\times 10^{-6}\ J

2.98273 V

Explanation:

C_1=25\ mu F

C_2=31\ mu F

V = Voltage = 6 V

Equivalent capacitance is given by

\dfrac{1}{C}=\dfrac{1}{C_1}+\dfrac{1}{C_2}\\\Rightarrow C=\dfrac{C_1C_2}{C_1+C_2}\\\Rightarrow C=\dfrac{25\times 10^{-6}\times 31\times 10^{-6}}{(25+31)\times 10^{-6}}\\\Rightarrow C=13.83928\times 10^{-6}\ F

Equivalent capacitance is 13.83928\times 10^{-6}\ F

Energy stored is given by

E=\dfrac{1}{2}CV^2\\\Rightarrow E=\dfrac{1}{2}\times 13.83928\times 10^{-6}\times 6^2\\\Rightarrow E=249.10704\times 10^{-6}\ J

Total energy stored is 249.10704\times 10^{-6}\ J

Charge is given by

Q=CV\\\Rightarrow Q=13.83928\times 10^{-6}\times 6\\\Rightarrow Q=83.03568\times 10^{-6}\ C

Voltage is given by

V_1=\dfrac{Q}{C_1}\\\Rightarrow V_1=\dfrac{83.03568\times 10^{-6}}{25\times 10^{-6}}\\\Rightarrow V_1=3.3214272\ V

E_1=\dfrac{1}{2}C_1V_1^2\\\Rightarrow E_1=\dfrac{1}{2}\times 25\times 10^{-6}\times 3.3214272^2\\\Rightarrow E_1=137.89848\times 10^{-6}\ J

Energy strored in C1 is 137.89848\times 10^{-6}\ J

V_2=\dfrac{Q}{C_2}\\\Rightarrow V_2=\dfrac{83.03568\times 10^{-6}}{31\times 10^{-6}}\\\Rightarrow V_2=2.67857\ V

E_2=\dfrac{1}{2}C_2V_2^2\\\Rightarrow E_2=\dfrac{1}{2}\times 31\times 10^{-6}\times2.67857^2\\\Rightarrow E_2=111.20842\times 10^{-6}\ J

Energy stored in C2 is 111.20842\times 10^{-6}\ J

E=E_1+E_2\\\Rightarrow E=137.89848\times 10^{-6}+111.20842\times 10^{-6}\\\Rightarrow E=249.107\times 10^{-6}\ J

So, the energy is equivalent

Equivalent capacitance

C=C_1+C_2\\\Rightarrow C=25+31\\\Rightarrow C=56\times 10^{-6}\ F

E=\dfrac{1}{2}CV^2\\\Rightarrow V=\sqrt{\dfrac{2E}{C}}\\\Rightarrow V=\sqrt{\dfrac{2\times 249.107\times 10^{-6}}{56\times 10^{-6}}}\\\Rightarrow V=2.98273\ V

The voltage would be 2.98273 V

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4 years ago
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