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3 years ago

6

3 points

1 answer:

blagie [28]3 years ago

8 0

Answer:

A and D

Explanation:

Acceleration is the active change in speed, increasing or decreasing.

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A radio wave has a speed of 3.00 x10^8 and a frequency of 100 MHz. What is the wavelength?

dlinn [17]

Answer:

Wavelength of radio is wave is 3 m

Explanation:

Wavelength of radio is wave is

$\lambda=\frac{v}{f}$

where

$v=3 \times 10^8 m\s\\f=100 Mhz$

wavelength is

$\lambda=\frac{3\times 10^8}{100\times 10^6} \\\\\lambda=3 m\\$

5 0

3 years ago

Using Ohm’s Law, explain how resistance changes in relation to current, assuming that voltage remains constant.

Cerrena [4.2K]

V=IR so voltage is directly proportional to current. So for a given resistance increasing the voltage will result in a high current as well. This is because resistance is proportional to the voltage over the current. Ex: I=V/R
Hope this helped. THANKYOU for asking. <span />

7 0

3 years ago

"Two long parallel wires 24.0 cm apart carry currents of 3.0 A and 8.0 A in the same direction. How far from the wire carrying 3

avanturin [10]

Answer:

6.5454 m

Explanation:

Let the distance from the wire carrying 3 A current is x

Then the distance from the the carrying current 8 A is 24-x

We know that magnetic field due to long wire is given by $B=\frac{\mu _0i}{2\pi r}$

It is given that magnetic field is zero at some distance so

$\frac{\mu _0i_1}{2\pi x}=\frac{\mu _0i_2}{2\pi (24-x)}$

Here $i_1=3\ A \ and\ i_2=8\ A$

So $\frac{3}{x}=\frac{8}{24-x}=6.5454\ m$

3 0

3 years ago

Can anyone help me with questions a and c

Ganezh [65]

Answer:

a)

n=sin i/sin r

n= -0.305/-0.428

n=0.713

b)

sin c=1/n

sin c=1/0.713

sin c= 1.403

c=sin⁻¹(1.403)

c= 40.842°

Explanation:

i hope it will be helpful

plzzz mark as brainliest

5 0

3 years ago

dybincka [34]

Answer:

1. 218.55 N

2. $30.96^{o}$

3. $2.1 m/s^{2}$

Explanation:

Part 1;

Net force $F=mg sin \theta$ where m is mass, g is gravitational force and $\theta$ is the angle of inclination

$F= 46*9.8*sin 29^{o}= 218.55N$

Frictional force, $F_{r}$ is given by

$F_{r} = \mu_{s}mg cos \theta$ where $\mu_{s}$ is the coefficient of static friction

$F_{r} = 0.6*46*9.8 cos 29$

$F_{r}=236.57N$

Since $F_{r}>F$ , therefore, the block doesn’t slip and the frictional force acting is mgh=218.55N

Part 2.

Using the relationship that

Frictional force $F_{s} = \mu_{s} mg cos \theta$

$mg sin \theta =\mu_{s} mg cos \theta$

$\mu_{s}= \frac {sin \theta}{cos \theta}$

$\mu_{s}= tan \theta$

The maximum angle of inclination $\theta = tan^{-1} \mu_{s}$

$\theta = tan^{-1} (0.6)$

$\theta= 30.96^{o}$

Part 3:

Net force on the object is given by

$ma = mg sin 38 - \mu_{k} mg cos 38$ where $\mu_{k}$ is the coefficient of kinetic friction

$a = g ( sin 38 - \mu_{k} cos 38 )$

= 9.8 ( sin 38 - (0.51) cos 38 )

= $2.1m/s^{2}$

7 0

4 years ago