Answer:

Explanation:
In a LC circuit The time constant τ is the time necessary for 60% of the total current (maximum current), pass through the inductor after a direct voltage source has been connected to it. The time constant can be calculated as follows:

Therefore, the time needed for the current to reach a fraction f = 0.6(60%) of its maximum value is:

Answer:
0.558 atm
Explanation:
We must first consider that both gases behaves like ideal gases, so we can use the following formula: PV=nRT
Then, we should consider that, whithin a mixture of gases, the total pressure is the sum of the partial pressure of each gas:
P₀ = P₁ + P₂ + ....
P₀= total pressure
P₁=P₂= is the partial pressure of each gass
If we can consider that each gas is an ideal gas, then:
P₀= (nRT/V)₁ + (nRT/V)₂ +..
Considering the molecular mass of O₂:
M O₂= 32 g/mol
And also:
R= ideal gas constant= 0.082 Lt*atm/K*mol
T= 65°C=338 K
4.98 g O₂ = 0.156 moles O₂
V= 7.75 Lt
Then:
P°O₂=partial pressure of oxygen gas= (0.156x0.082x338)/7.75
P°O₂= 0.558 atm
The only thing we know about so far that can shift wavelengths of light
to longer wavelengths is when the source of the light is moving away
from the observer.
When we look at the light from distant galaxies, the light from them is
always shifted to longer wavelengths than it SHOULD have.
AND ... The farther away from us a galaxy IS, the MORE its light is
shifted to wavelengths longer than it should have.
So far, this indicates to us that the whole universe is expanding.
That's the only way to understand what we see, because that's
the only thing we know of that can shift light to longer wavelengths.
By the way ... The most interesting thing about these observations
and measurements is: When astronomers see this light from distant
galaxies and measure the wavelengths, how do they know how far
the wavelengths shifted ? How do they know what the wavelengths
SHOULD be ?
I'll leave you to read about that in the next few years.
Answer:
97 minutes and 12 seconds
Explanation:
Let x be the total time
From the first statement

Total time of Dara's exercise is 14580 seconds
40 %


Time when she had completed 40% was 1 hour 37 minutes and 12 seconds