Answer:
The driver's average velocity is 82.35 km/h.
Explanation:
Given:
The motion of the driver can be divided into 3 parts:
i. Displacement of the driver in 1.5 hours = 135 km
ii. Rest for 45 minutes.
iii. Displacement in next 2 hours = 215 km
The direction of motion remains same (east).
Now, total displacement of the driver is,
km.
Rest time is 45 minutes. Converting it to hours, we need to use the conversion factor
hour.
So, 45 minutes in hours is equal to
hours.
Now, total time taken for the complete journey is, 
Average velocity is given as:

Therefore, the driver's average velocity is 82.35 km/h
Answer:
1.35208 m/s
Explanation:
Speed of the boat = 0.75 m/s
Distance between the shores = 100 m
Time = Distance / Speed

Time taken by the boat to get across is 133.33 seconds
Point C is 150 m from B
Speed = Distance / Time

Velocity of the water is 1.125 m/s
From Pythagoras theorem

So, the man's velocity relative to the shore is 1.35208 m/s
Answer:
A. 4148 J/K/Kg
B. 4148 J/K/L
Explanation:
A. Heat capacity per unit mass is known as the specific heat capacity, c.
C = Heat capacity/mass(kg)
C = (523 J/K) / 0.125 Kg = 4148 J/K/Kg
B. Volume of water = mass/density
Density of water = 1 Kg/L
Volume of water = 0.125 Kg/ 1Kg/L
Volume of water = 0.125 L
Heat capacity per unit volume = (523 J/K) / 0.125 L
Heat capacity per unit volume = 4148 J/K/L
Answer:
The banking angle is 23.84 degrees.
Explanation:
Given that,
Radius of the curve, r = 194 m
Speed of the car, v = 29 m/s
On the banked curve, the centripetal force is balanced by the force of friction such that,




So, the banking angle is 23.84 degrees. Hence, this is the required solution.
Answer:
0.34 m
Explanation:
From the question,
v = λf................ Equation 1
Where v = speed of sound, f = frequency, λ = Wave length
Make λ the subject of the equation
λ = v/f............... Equation 2
Given: v = 340 m/s, f = 500 Hz.
Substitute these values into equation 2
λ = 340/500
λ = 0.68 m
But, the distance between a point of rarefaction and the next compression point, in the resulting sound is half wave length
Therefore,
λ/2 = 0.68/2
λ/2 = 0.34 m
Hence, the distance between a point of rarefaction and the next compression point, in the resulting sound is 0.34 m