Hello, for this applicate formula:
Vf² = Vo² + 2gh
Data:
Vf = Final Velocity = ¿?
Vo = Initial veloctiy = 0 m/s
g = Gravity = 9,81 m/s²
h = Height = 5 m
Replacing according our data:
Vf² = 0 m/s² + 2(9,81 m/s²)(5 m)
Vf² = 98,1 m²/s²
Vf = √98,1 m²/s²
Vf = 9,9 m/s
The final velocity will be <u>9,9 meters per second.</u>
Answer:
The body reading on the scale will increase.
Explanation:
The scale reading will definitely increase due to buoyancy of the ball. According to Archimedes' law which states that the magnitude of buoyancy force on the body is the same as the weight of the liquid which is pushed out when submerging the body. Therefore, the body reading on the scale will increase.
Answer:
a. the density will not change
b. D' = 0.125 D
So, the density will change by a factor of 0.125
Explanation:
a.
Density is the material property and the value of density is constant for all solid materials. So, when the dimensions of the a solid are increased, while the material is same, then the material must be added to the object for increasing its dimensions. So, with the increase in the volume, the mass of the object also increases. And as a result the density of the object remains constant.
Since, here the material remains the same.
<u>Therefore, the density will not change</u>
<u></u>
b.
Density = mass/Volume
D = m/V ------------ equation (1)
Now,
V = LWH ----------- equation (2)
Now, if each dimension increases by a factor of 2, the volume becomes:
V' = (2L)(2W)(2H)
V' = 8 LWH
using equation (2)
V' = 8 V
So, for constant mass, density becomes:
D' = m/V'
D' = m/8V
using equation (1)
D' = D/8
<u>D' = 0.125 D</u>
<u>So, the density will change by a factor of 0.125</u>
Water diffusion is called osmosis. Oxygen is a small molecule and it's nonpolar, so it easily passes through a cell membrane. Carbon dioxide, the byproduct of cell respiration, is small enough to readily diffuse out of a cell. Small uncharged lipid molecules can pass through the lipid innards of the membrane.