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2 years ago

Im asking for you're help Citizen I have a question for you Me

Mathematics

2 answers:

Studentka2010 [4]2 years ago

8 0

Answer:

No idea

Step-by-step explanation:

No idea for that either

KIM [24]2 years ago

8 0

Hope this helps, have a good day

Step-by-step explanation:

1. The bag contains fewer than 10 carrots

2.catherin3 biked farther than 10 miles

3.the chair is shorter than 20 in

4.carlos scored over 20 points

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Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

3 years ago

What are the domain and range of f(x) =4^x-8

Nutka1998 [239]

The domain in this equation is -7<x<infinty and the range is negative infinty<y<1.5

6 0

3 years ago

Which graph represents a quadratic function with a vertex at (0, 0)?

maxonik [38]

The 3rd one. (where the round part of the graph is at 0, 0) because that is where the y axis meets

7 0

3 years ago

Read 2 more answers

An in ground rectangular pool has a concrete pathway surrounding the pool. if the pool is 16 feet by 32 feet and the entire area

Anastasy [175]

1. Let's call:

x: the width of the walkway.
b: 2x+16 (there is a widht "x" of the walkway on each side).
h: 2x+32 (there is a widht "x" of the walkway on each side).
A: 924 ft^2 ( the area of the pool of including the walkway).

2. The area of a rectangle is:

A=(b)(h)

b: the base of the rectangle (2x+16)
a: the height of the rectangle (2x+32)

3. Then, we have a quadratic equation:

924=(2x+16)(2x+32)
4x^2+64x+32x+512-924=0
4x^2+96x-412=0

4. We apply the quadratic formula to find the value of "x":

x=(-b±√(b^2-4ac))/2a

x=3.71

The answer is: The width of the walkway is 3.71 ft

7 0

3 years ago

Drag the tiles to the boxes to form correct pairs. Not all tiles will be used. A car repair center services 920 cars in 2012. Th

OverLord2011 [107]

Answer:

N = 920(1+0.03)^4t

Step-by-step explanation:

According to the given statement a car repair center services 920 cars in 2012. The number of cars serviced increases quarterly at a rate of 12% per year after 2012.

Rate is 12 % annually

rate in quarterly = 12/4= 3%

We will apply the compound interest equation:

N=P( 1+r/n)^nt

N= ending number of cars serviced.

P= the number of cars serviced in 2012,

r = interest rate

n = the number of compoundings per year

t= total number of years.

Number of compoundings for t years = n*t = 4t

Initial number of cars serviced=920

The quarterly rate of growth = n=4

r = 3%

The growth rate = 1.03

Compound period multiplied by number of years = 920(1.03)^4t

Thus N = 920(1+0.03)^4t

N = number of cars serviced after t years...

5 0

3 years ago