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2 years ago

I need help with this and if so can you pls give an explanation?

Mathematics

1 answer:

fiasKO [112]2 years ago

8 0

Answer:

Step-by-step explanation:

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Identify the value of a if

Serga [27]

Answer:

a=1/3

Step-by-step explanation:

from the point on the graph

x=4 and y=8

substitute them into the equation:

y=a(x-2) (2x+4)

you will get

8=a(4-2) (2(4)+4)

8=a(2) (8+4)

8=a(2) (12)

8=2a×12

8=24a

divide both sides by 24

8/24=24a/24

1/3=a or a=1/3

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2 years ago

BRAINLIEST <br> Please answer these

zheka24 [161]

3.14 is used for pi.

6. r = $\sqrt{\frac{A}{\pi } }$

14.00

7. d = $\frac{c}{\pi }$

5.00

8. d = $2 \sqrt{\frac{A}{\pi } }$

23.01

9. r = $\frac{c}{2\pi }$

20.01

10. d $\pi$ = $2 \sqrt{{A}$

31 $\pi$

11. r $\pi$ = $\frac{c}{2}$

22.5 $\pi$

Hope this helps :)

6 0

2 years ago

X=4y,2x+y=18 solve by substitution show all work

Mkey [24]

Here is the math, did it on paper, sorry it’s blue. just add parenthesis around the x in the second equation and add what x equals. then solve as PEMDAS.

7 0

1 year ago

85 is greater than the difference of x and63

miss Akunina [59]

85 > x-63

This is how you would arrange the problem,

isolate the X by adding 63 to 85 to get 148,
Flip the inequality to <

resulting in X<148.

8 0

3 years ago

2. In a given population of two-earner male-female couples, male earnings have a mean of $40,000 per year and a standard deviati

Kobotan [32]

Answer: $85,000

Step-by-step explanation:

Given : In a given population of two-earner male-female couples, male earnings have a mean of $40,000 per year and a standard deviation of $12,000.

$\mu_M=40,000\ \ ;\sigma_M=12,000$

Female earnings have a mean of $45,000 per year and a standard deviation of $18,000.

$\mu_F=45,000\ \ ;\sigma_F=18,000$

If C denote the combined earnings for a randomly selected couple.

Then, the mean of C will be :-

$\mu_c=\mu_M+\mu_F\\\\=40,000+45,000=85,000$

Hence, the mean of C = $85,000

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2 years ago