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natta225 [31]
2 years ago
15

Which of the following tools is not used for measurement?

Chemistry
1 answer:
Verdich [7]2 years ago
8 0

Answer:

tape measure

Explanation:

I am helping

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How many grams of sulfur in 4.20 x 1021 atoms of sulfur?
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Write a full chemical equation for the reactions between magnesium and sulfuric acid
melamori03 [73]

Answer:

magnesium + hydrochloric acid → hydrogen gas + magnesium chloride

explanation:

the nitrogen in HNO3 is in the +5 oxidation state and is easily reduced. The reduction would result in the oxidation of the hydrogen gas, forming the water once again.The sulfur in H2SO4 is also in its highest oxidation state, +6.

<em>Hope</em><em> this</em><em> helps</em><em> </em><em>:</em><em>)</em>

6 0
3 years ago
In ionic compounds, ________ lose their valence electrons to form positively charged ________. nonmetals, anions metals, polyato
Keith_Richards [23]
Answer:
            <span>In ionic compounds, <u>Metals</u> lose their valence electrons to form positively charged Cations. 

Explanation:
                   Metals have the ability to loose elctrons readily. For example metals of Group IA and Group IIA readily looses electrons in order to obtain Noble Gas Configuration. On the other hand Non-metals tends to gain electrons and acquire negative charge. While Ions are made when an an element gain or loose electrons. After loosing electrons element get positive charge which is called as Cation while on gaining electron it gets negative charge called as Anion.</span>
6 0
3 years ago
Read 2 more answers
A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f
Allisa [31]

Answer:

The mass of water m_{w} = 39.18 gm

Explanation:

Mass of iron m_{iron} = 32.5 gm

Initial temperature of iron T_{1} = 22.4°c = 295.4 K

Specific heat of iron  C_{iron} = 0.448 \frac{KJ}{kg K}

Mass of water = m_{w}

Specific heat of water  C_{w} = 4.2 \frac{KJ}{kg  K}

Initial temperature of water T_{2} = 336 K  

Final temperature after equilibrium T_{f} = 59.7°c = 332.7 K

When iron rod is submerged into water then

Heat lost by water  = Heat gain by iron rod

m_{w} C_{w} (T_{2} - T_{f} ) =  m_{iron} C_{iron} ( T_{f} - T_{1} )

Put all the values in above formula we get

m_{w} × 4.2 × ( 336 - 332.7 ) = 32.5 × 0.448 × ( 332.7 - 295.4 )

m_{w} = 39.18 gm

Therefore the mass of water m_{w} = 39.18 gm

8 0
2 years ago
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