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lys-0071 [83]
3 years ago
12

How long must a 400w electrical engine work in order to produce 300kj of work

Physics
1 answer:
vladimir1956 [14]3 years ago
8 0

Answer:

300000 J / 400 J/s = 750 s = 12.5 minutes

Explanation:

You might be interested in
A golf club consists of a shaft connected to a club head. The golf club can be modeled as a uniform rod of length ℓ and mass m1
slega [8]

Answer:

 m₁ (R +ℓ/2) / /( m₁ + m₂ )

Explanation:

We shall consider centre of the club's head  as origin .

The centre of mass of the rod attached with sphere will be away from the centre of sphere by a distance

= R + ℓ /2 and its mass is m₁

mass of sphere is m₂ and distance of its centre of mass from origin is zero

So required CM = m₁ x₁ + m₂ x₂ / ( m₁ + m₂ )

= m₁ (R + ℓ /2) + m₂ x 0 /( m₁ + m₂ )

=  m₁ (R +ℓ/2) / /( m₁ + m₂ )

5 0
3 years ago
Pigments are always made of natural materials
Kobotan [32]
It seems that you have missed the necessary options for us to answer this question so I had to look for it. Anyway, the answer to the given statement is FALSE. Pigments are NOT always made of natural materials. Pigments can either be man-made or the one that occurred naturally as what you see in our environment. Hope this helps.
5 0
3 years ago
A boy at a football field practice kicked a 0.500-kg ball with a force of 100N. How fast will the ball move after reaching a dis
Tpy6a [65]

Answer:

v(7) = 52.915 m/s

Explanation:

First, find the value for acceleration.

F = ma

100 = .5 * a

a = 200 m/s²

Next find the velocity at x = 7 using kinematic equations.

v² = v₀² + 2a(Δx)

v² = (0)² + 2(200)(7)

v = \sqrt{2800}

v = 52.915 m/s

3 0
3 years ago
21. Which oi the following is something that all living organisms have in common
irga5000 [103]
They need resources such as food and sometimes water
6 0
4 years ago
A motor keep a Ferris wheel (with moment of inertia 6.97 × 107 kg · m2 ) rotating at 8.5 rev/hr. When the motor is turned off, t
Talja [164]

Answer:

P = 133.13 Watt

Explanation:

Initial angular speed of the ferris wheel is given as

\omega_i = 2\pi f

\omega_i = 2\pi(8.5/3600)

\omega_i = 0.015 rad/s

final angular speed after friction is given as

\omega_f = 2\pi f

\omega_f = 2\pi(7.5/3600)

\omega_f = 0.013 rad/s

now angular acceleration is given as

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

\alpha = \frac{0.015 - 0.013}{15}

\alpha = 1.27 \times 10^{-4} rad/s^2

now torque due to friction on the wheel is given as

\tau = I \alpha

\tau = (6.97 \times 10^7)(1.27 \times 10^{-4})

\tau = 8875.3 N m

Now the power required to rotate it with initial given speed is

P = \tau \omega

P = 8875.3 \times 0.015

P = 133.13 Watt

8 0
3 years ago
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