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Zina [86]
3 years ago
7

A compound whose molecules contain one boron atom and three fluorine atoms would be named monoboron fluoride. Please select the

best answer from the choices provided T F
Physics
1 answer:
Slav-nsk [51]3 years ago
5 0
I know it is false...............

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One object is at rest, and another is moving. The two collide in a one-dimensional, completely inelastic collision. In other wor
zhannawk [14.2K]

Answer:

Part a)

v = 16.52 m/s

Part b)

v = 7.47 m/s

Explanation:

Part a)

(a) when the large-mass object is the one moving initially

So here we can use momentum conservation as the net force on the system of two masses will be zero

so here we can say

m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v

since this is a perfect inelastic collision so after collision both balls will move together with same speed

so here we can say

v = \frac{(m_1v_{1i} + m_2v_{2i})}{(m_1 + m_2)}

v = \frac{(8.4\times 24 + 3.8\times 0)}{3.8 + 8.4}

v = 16.52 m/s

Part b)

(b) when the small-mass object is the one moving initially

here also we can use momentum conservation as the net force on the system of two masses will be zero

so here we can say

m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v

Again this is a perfect inelastic collision so after collision both balls will move together with same speed

so here we can say

v = \frac{(m_1v_{1i} + m_2v_{2i})}{(m_1 + m_2)}

v = \frac{(8.4\times 0 + 3.8\times 24)}{3.8 + 8.4}

v = 7.47 m/s

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3 years ago
Which statement about covalent bonds is true
g100num [7]
In covalent bonds the atoms share electrons.
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A student woke up in the morning and checked the rain gauge in her backyard. The rain gauge was empty, but the grass was moist.
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It would most likely be C
Welcome!  :P
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Please help me I have been struggling
disa [49]
  1. High/low notes have high/low frequency, not high/low amplitude.
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3 years ago
Relationship between voltage, resistance and current in a circuit
Lena [83]

Answer:

V = I×R

where -

V = potential difference across

I = current flowing in the circuit

R = Equivalent Resistance in the circuit

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