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riadik2000 [5.3K]
3 years ago
7

When on object’s spectral lines are shifted from their rest wavelengths to longer wavelengths, we say that the object’s spectrum

shows a redshift. When the lines are shifted to shorter wavelengths, we say that the object’s spectrum shows a blueshift. Which statement about an blueshift and a redshift is true?
Physics
1 answer:
neonofarm [45]3 years ago
4 0

Answer:

Both statements are true.

Explanation:

When a celestial object (stars, galaxies) is moving away from an observer its spectral lines¹ will be shifted to the red part of the spectrum² (longer wavelength), in the other hand if the celestial body is moving toward the observer, the spectral lines will be shifted to the blue part of the spectrum (shorter wavelength). That is known as the Doppler shift.

This Doppler shift can be explained with the Doppler Effect³, which is defined for the case of light as:    

\frac{\Delta \lambda}{\lambda_{0}} = \frac{v}{c}    (1)

Where \Delta \lambda is the wavelength shift, \lambda_{0} is the rest wavelength, v is the velocity of the source and c is the speed of light.

This redshift in distant galaxies is a strong evidence for the expansion of the universe. Equation 1 also allows the measurement of radial velocity from celestial objects.  

Summary:  

Blueshift:

\lambda

Redshift:

\lambda >\lambda_{0}

¹Spectral lines: Determines the presence of particular elements in the photosphere of an star.

²Spectrum: Decomposition of light in its characteristic colors (wavelengths).

³Doppler Effect: Change in the frequency of a wave as a consequence of the movement from a source relative to an observer or vice versa.

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marin [14]
The answer is D, the amount of energy stays the same.
3 0
3 years ago
If the mass of the sun is 1x, at least one planet will fall into the habitable zone if I place a planet in orbits___, ____, ____
Minchanka [31]

If the mass of the sun is 1x, at least one planet will fall into the habitable zone. if I place a planet in orbits 1, 3, 5 , 6 and all planets will orbit the sun successfully.

<h3>
What are planets?</h3>

Planets are the large spherical shaped objects that rotate about the Sun in the elliptical orbits.

Planets are shaped from Planetary cloud. The dust storm and gases gathers under its own weight. The dense matter beginnings pivoting at high paces and accumulates more mass. The center structures, the star and rest of it ultimately levels into a curved plate from which planet is formed.

Thus,  if I place a planet in orbits 1, 3, 5 , 6 and all planets will orbit the sun successfully.

Learn more about planets.

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5 0
2 years ago
A 5cm tall object is placed 4cm in front of a converging lens that has a focal length of 8cm. Where is the image located in ____
OverLord2011 [107]

Answer:

a. -8 cm

Explanation:

d_{o} = distance of the object = 4 cm

d_{i} = distance of the image = ?

f = focal length of the converging lens  = 8 cm

using the lens equation

\frac{1}{d_{o}} + \frac{1}{d_{i}} = \frac{1}{f}

\frac{1}{4} + \frac{1}{d_{i}} = \frac{1}{8}

d_{i} = - 8 cm

4 0
2 years ago
A sprinter set a high school record in track and field, running 200.0 m in 20.6 s . what is the average speed of the sprinter in
Paraphin [41]

Answer : The average speed of the sprinter is, 34.95 Km/hr

Solution :

Average velocity : It is defined as the distance traveled by the time taken.

Formula used for average velocity :

v_{av}=\frac{d}{t}

where,

v_{av} = average velocity

d = distance traveled = 200 m

t = time taken = 20.6 s

Now put all the given values in the above formula, we get the average velocity of the sprinter.

v_{av}=\frac{200m}{20.6s}\times \frac{3600}{1000}=34.95Km/hr

conversion :

(1 Km = 1000m)

(1 hr = 3600 s)

Therefore, the average speed of the sprinter is, 34.95 Km/hr

8 0
2 years ago
Read 2 more answers
A girl playing tug-of-war with her dog pulls the dog a distance of 8.0m by exerting a force at an angle of 18° with the horizont
AnnZ [28]

Answer:

25 N

Explanation:

Work is a product of force and perpendicular distance moved.

W=Fd where F is force exerted and d is perpendicular distance.

However, for this case, the distance is inclined hence resolving it to perpendicular so that it be along x-axis we have distance as dcos\theta

Therefore, W=Fdcos\theta

Making F the subject of the formula then

F=\frac {W}{dcos\theta} where \theta is the angle of inclination. Substituting 190 J for W then 18 degrees for \theta and 8 m for d then

F=\frac {190}{8cos18^{\circ}}\approx 25N

3 0
2 years ago
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