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3 years ago

What is 6,372,079,003 in word form

Mathematics

1 answer:

Minchanka [31]3 years ago

3 0

<span>six billion,three hundred seventy-two million, seventy-nine thousand,three
</span>
Hope this helps :D

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In circle O, RT and SU are diameters.

nataly862011 [7]

In circle O, RT and SU are diameters. mArc R V = mArc V U = 64°. Thus, option C is correct.

Given that:

mArc R V = mArc V U,

Angle S O R = 13 x degrees

Angle T O U = 15 x - 8 degrees

<h3>How to calculate the angle TOU ?</h3>

∠SOR = ∠TOU (Vertically opposite angles are equal).

Therefore:

13 x = 15x - 8

Subtracting 13x from both sides

13x - 13x = 15x - 8 - 13x

0 = 15x - 13x - 8

2x - 8 = 0

Adding 8 to both sides:

2x - 8 + 8 = 0 + 8

2x = 8

2x/2 = 8/2

x = 4

∠SOR = 13x

= 13(4)

= 52°

∠TOU = 15x - 8

= 15(4) - 8

= 60 - 8

= 52°

Let a = mArc R V = mArc V U

Therefore:

mArc R V + mArc V U + ∠TOU = 180 (sum of angles on a straight line)

Substituting:

a + a + 52 = 180

2a = 180-52

2a = 128

a = 128/2

a= 64°

mArc R V = mArc V U = 64°

In circle O, RT and SU are diameters. mArc R V = mArc V U = 64°. Thus, option C is correct.

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

6 0

2 years ago

Given the formula a = s2 + 3b - c , find the value of a when s = 7, b = 13 and c = -24.

galben [10]

Answer:

a = 112

Step-by-step explanation:

$a =s^{2} +3b-c$

Given that,

s = 7

b = 13

c = (-24)

Let's solve for a now.

$a =s^{2} +3b-c$

$a = 7^{2} +3*13-(-24)\\$

$a=49+39+24\\$

$a=88+24$

$a=112$

Hope this helps you.

Let me know if you have any other questions :-)

3 0

3 years ago

Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

$P(x \ge 60) \approx P(z > 1.34)$