1. find the area of the two triangles, including the shaded section. the formula for this is a=1/2bh
the height and base are both 24 inches. this is because you add the 10 from the side of the square to the 14 that is given
so:
a=1/2(24)(24)
a=(12)(24)
a=288 sq. inches
since there are two triangles, you would multiply the area by 2
a=2(288)
a=576 sq. inches
now, since you only need the unshaded section, you have to take away the shaded section, which is a square. to do this, you must calculate the area of the square and take it away from the area of both triangles.
a=576-(lw)
a=576- (10)(10)
a=576-100
a=476 sq. inches
that is your answer
Answer:
100π
Step-by-step explanation:
Area of a circle formula: πr²
The radius would be half of 20 m
So the radius, r is 10 m
Plug that in
πr²=π·10²=100π
So in your circle their is a terminal point who is assigned by the value of P(x,y) and lies or determined by teh value of T=4pi/3. To get the coordinates of this terminal point first is to know what is the angle of the T and the answer is (-1/2, -sqrt(3)/2)
