Answer:
3
Step-by-step explanation:

And,
$ \sum (2i+1)= \sum (2i)+ \sum_{i=1} ^{4} (1) $
$=\sum_{i=1} ^{4}(2i) + 1+1+1+1 $
$=\boxed{\Big(\sum_{n=1} ^{4}(2n)\Big) +4}.... \text{Variable in Summation doesn't matter}$
Hence the difference is 3.
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Answer:
g(x) is shifted 4 units left and 6 units down from f(x).
Step-by-step explanation:
The parent function is:
f(x).
The child function is:

Transformation 1:

Shifting a function f(x) a units to the left is finding f(x + a). So g(x) = f(x + 4) is f(x) shifted 4 units to the left.
Transformation 2:

Subtracting a function f(x) by a constant a is the same as shifting the function a units down. So subtracting by 6 is shifting the function 6 units down. Thus, the correct answer is:
g(x) is shifted 4 units left and 6 units down from f(x).