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2 years ago

A baker used 25% of the eggs that were bought to make cakes. If 60 eggs were used, what was the total

Mathematics

1 answer:

ElenaW [278]2 years ago

8 0

240 eggs were bought. A trick you can do when it’s 25% is 4. So for this I multiplied 60 by 4 which would give the 100%

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Vertex (0,0) focus (0,-1)<br> A) y=1/4 x^2<br> B) y=-1/4x^2<br> C) y=1/16x^2<br> D) y=-1/16x^2

hichkok12 [17]

Answer:B

Step-by-step explanation:

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2 years ago

If a two-sided null hypothesis is rejected for a single mean at a given significance level, the corresponding one-sided null hyp

maria [59]

Answer:

my hypothesis is that the answer is on page 31 of Harry potter and the Prisoner of Azkaban, it'll be the 48th word. God speed old chum

Step-by-step explanation:

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3 years ago

Simplify : 14z + 8y - 5 + 9y - 10z

kirill115 [55]

4z+17y-5
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2 years ago

Read 2 more answers

Please I need help with differential equation. Thank you

Inga [223]

1. I suppose the ODE is supposed to be

$\mathrm dt\dfrac{y+y^{1/2}}{1-t}=\mathrm dy(t+1)$

Solving for $\dfrac{\mathrm dy}{\mathrm dt}$ gives

$\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{y+y^{1/2}}{1-t^2}$

which is undefined when $t=\pm1$ . The interval of validity depends on what your initial value is. In this case, it's $t=-\dfrac12$ , so the largest interval on which a solution can exist is $-1\le t\le1$ .

2. Separating the variables gives

$\dfrac{\mathrm dy}{y+y^{1/2}}=\dfrac{\mathrm dt}{1-t^2}$

Integrate both sides. On the left, we have

$\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\int\frac{\mathrm dz}{z+1}$

where we substituted $z=y^{1/2}$ - or $z^2=y$ - and $2z\,\mathrm dz=\mathrm dy$ - or $\mathrm dz=\dfrac{\mathrm dy}{2y^{1/2}}$ .

$\displaystyle\int\frac{\mathrm dy}{y^{1/2}(y^{1/2}+1)}=2\ln|z+1|=2\ln(y^{1/2}+1)$

On the right, we have

$\dfrac1{1-t^2}=\dfrac12\left(\dfrac1{1-t}+\dfrac1{1+t}\right)$

$\displaystyle\int\frac{\mathrm dt}{1-t^2}=\dfrac12(\ln|1-t|+\ln|1+t|)+C=\ln(1-t^2)^{1/2}+C$

$2\ln(y^{1/2}+1)=\ln(1-t^2)^{1/2}+C$

$\ln(y^{1/2}+1)=\dfrac12\ln(1-t^2)^{1/2}+C$

$y^{1/2}+1=e^{\ln(1-t^2)^{1/4}+C}$

$y^{1/2}=C(1-t^2)^{1/4}-1$

I'll leave the solution in this form for now to make solving for $C$ easier. Given that $y\left(-\dfrac12\right)=1$ , we get

$1^{1/2}=C\left(1-\left(-\dfrac12\right)^2\right))^{1/4}-1$

$2=C\left(\dfrac54\right)^{1/4}$

$C=2\left(\dfrac45\right)^{1/4}$

and so our solution is

$\boxed{y(t)=\left(2\left(\dfrac45-\dfrac45t^2\right)^{1/4}-1\right)^2}$

3 0

3 years ago

A go kart top speed is 607,200 feet per hour. What is the speed in miles per hour

PolarNik [594]

One mile equals 5280 feet so

607,200/5280=115

So it’s 115 miles per hour

8 0

3 years ago