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astraxan [27]
3 years ago
11

A body initially at rest is accelerated at a constant rate for 5.0 seconds in the positive x direction. If the final speed of th

e body is 20.0 m/s, what was the body's acceleration?
Physics
1 answer:
forsale [732]3 years ago
3 0

Answer:

a=4\ m/s^2

Explanation:

Given that,

Initial speed of a body, u = 0

Final speed of the body, v = 20 m/s

Time, t = 5 s

We need to find the acceleration of the body. We know that the acceleration of an object is equal to the rate of change of velocity divided by time taken. So,

a=\dfrac{v-u}{t}\\\\a=\dfrac{20-0}{5}\\\\a=4\ m/s^2

So, the body's acceleration is equal to 4\ m/s^2.

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A bicycle wheel of radius 0.28 m rolls down a hill without slipping. Its linear velocity increases constantly from 0 to 8 m/s in
Marina86 [1]

Answer:

10.989 rad/s²

Explanation:

Angular Acceleration: This is the acceleration of a body that undergoes a circular motion. The S.I unit of angular acceleration is rad/s²

The expression for angular acceleration is given as

a = αr.............. Equation 1

Where a = linear acceleration, α = angular acceleration, r = radius.

make α the subject of the equation

α = a/r............. Equation 2.

But,

a = (v-u)/t ............. Equation 3

Where v = final velocity, u = initial velocity, t = time.

substitute equation 3 into equation 2

α = (v-u)/rt............ Equation 4

Given: v = 8 m/s, u = 0 m/s, r = 0.28 m, t = 2.6 s

Substitute into equation 4

α = (8-0)/(0.28×2.6)

α = 8/0.728

α = 10.989 rad/s²

5 0
3 years ago
Fossils reveal which of the following about a species or organism
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8 0
4 years ago
Under what conditions will a moving 0.030 kg marble and a moving 2.43 kg rock have the same kinetic energy
Anestetic [448]

Answer:

To have the same kinetic energy the speed of the marble must be 9 times the speed of rock.

Explanation:

The general formula of kinetic energy is given as follows:

K.E = \frac{1}{2}mv^{2}

where,

K.E = Kinetic Energy

m = mass of the object

v = speed of the object

So, for the marble and rock to have same kinetic energy, we can write:

K.E_{marble} = K.E_{rock}\\\\\frac{1}{2}m_{marble}v_{marble}^{2} =  \frac{1}{2}m_{rock}v_{rock}^{2}\\\\(0.03\ kg)v_{marble}^{2} = (2.43\ kg)v_{rock}^{2}\\\\taking\ square\ root\ on\ both\ sides:\\v_{marble} = \sqrt{\frac{2.43\ kg}{0.03\ kg}}v_{rock}\\\\v_{marble} = 9\ v_{rock}

<u>Hence, to have the same kinetic energy the speed of the marble must be 9 times the speed of rock.</u>

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3 years ago
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