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Viktor [21]
2 years ago
12

Larger animals have sturdier bones than smaller animals. A mouse's skeleton is only a few percent of its body weight, compared t

o 16% for an elephant. To see why this must be so, recall that the stress on the femur for a man standing on one leg is 1.4% of the bone's tensile strength.
Suppose we scale this man up by a factor of 10 in all dimensions, keeping the same body proportions. (Assume that a 70 kg person has a femur with a cross-section area (of the cortical bone) of 4.8 x 10−4 m2, a typical value.)
Both the inside and outside diameter of the femur, the region of cortical bone, will increase by a factor of 10. What will be the new cross-section area?
Physics
1 answer:
Rama09 [41]2 years ago
7 0

Answer:

a_s=4.8\times  10^{-2}~m^2

Explanation:

Given:

cross sectional area of the bone, a=4.8 \times 10^{-4} ~m^2

factor of up-scaling the dimensions, s=10

Since we need to find the upscaled area having two degrees of the dimension therefore the scaling factor gets squared for the area being it in 2-dimensions.

The scaled up area is:

a_s=a\times s^2

a_s=[4.8 \times 10^{-4}]\times 10^2

a_s=4.8\times  10^{-2}~m^2

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Ignoring air resistance and the little friction from the plastic tube, the magnet was a freely-falling object in each trial. If
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Explanation:

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e m f=-N \frac{\Delta \Phi}{\Delta T}

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A 500kg car skids to a stop at a traffic light, leaving behind a 18.25m skid mark as it comes to a rest. Assuming that the car i
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Answer:

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We have given mass of the car m = 500 kg

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From second equation of motion

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We know that acceleration is given by

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5.76=\mu\times  9.81

\mu =0.587

So coefficient of friction will be 0.587

6 0
3 years ago
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