7. A student walks 3 blocks east, 4 blocks north, and 3 blocks west. What is the displacement of the student? (5 points)
2 answers:
You might be interested in
Answer:
It is unsafe
Explanation:
v = Velocity of car = 34 m/s
r = Radius of turn = 190 m
= Coefficient of static friction = 0.5
m = Mass of car = 1600 kg
g = Acceleration due to gravity = 9.81 m/s²
The centripetal force is given by
The frictional force is given by
If the centripetal force is greater than the frictional force then the car will slip which makes it unsafe.
Here, the centripetal force is greater than the frictional force which makes it unsafe to drive it at that speed.
Answer:
No, the truck will not cross the barrier.
The closeness of the truck to the barrier is of 21.875 m
Solution:
As per the question:
Velocity of the truck, v = 25.0 m/s
Acceleration of the truck, a = - 4
Now,
Since, the barrier at a distance of 100 m. Thus in order to check whether the truck hit the barrier or not, we will see the distance, d it covers by using the kinematic eqn:
Final velocity, v' = 0 m/s
Initial velocity = v
Now,
d = 78.125 m
Thus the truck will not cross the barrier.
Distance between the barrier and the truck:
100 - 78.125 = 21.875 m