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KIM [24]
3 years ago
5

Gwen is researching the effects of a small asteroid impact in an area that has started to regrow after being hit ten years ago.

She considers the event to be a long-term change because the species of plants that were present had to start completely over from seeds after all of the plants in the area were killed by the impact. What is the error in Gwen’s thinking?
Physics
2 answers:
velikii [3]3 years ago
5 0

Answer:

D) This is a short-term change, not a long-term change.

Explanation:

Bumek [7]3 years ago
3 0

Answer:

Gwen’s assumption of asteroid hit as long term change is incorrect. Asteroid hit is not a long term change, instead, it is a short term change.  

Explanation:

Examples of short term changes are drought, flood, volcanic eruption, etc. A short term change occurs quickly and can immediately affect organisms but it doesn’t become a reason for species extinction. The effects of a short term change don’t prevail over a long span of time.

Examples of long term changes are ice age, global warming, deforestation, etc. Unlike a short term change, it takes time but the consequences are far-reaching. It can lead to species extinction.

In this question, asteroid hit is a quick and unexpected hazard, unlike the slow long term environmental changes.

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Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars
zhuklara [117]

Kepler's third law is used to determine the relationship between the orbital period of a planet and the radius of the planet.

The distance of the earth from the sun is 1.50 \times 10^{11}\;\rm m.

<h3>What is Kepler's third law?</h3>

Kepler's Third Law states that the square of the orbital period of a planet is directly proportional to the cube of the radius of their orbits. It means that the period for a planet to orbit the Sun increases rapidly with the radius of its orbit.

T^2 \propto R^3

Given that Mars’s orbital period T is 687 days, and Mars’s distance from the Sun R is 2.279 × 10^11 m.

By using Kepler's third law, this can be written as,

T^2 \propto R^3

T^2 = kR^3

Substituting the values, we get the value of constant k for mars.

687^2 = k\times (2.279 \times 10^{11})^3

k = 3.92 \times 10^{-29}

The value of constant k is the same for Earth as well, also we know that the orbital period for Earth is 365 days. So the R is calculated as given below.

365^3 = 3.92\times 10^{-29} R^3

R^3 = 3.39 \times 10^{33}

R= 1.50 \times 10^{11}\;\rm m

Hence we can conclude that the distance of the earth from the sun is 1.50 \times 10^{11}\;\rm m.

To know more about Kepler's third law, follow the link given below.

brainly.com/question/7783290.

6 0
3 years ago
Show that the speed with which a projectile leaves the ground is equal to its speed just before it strikes the ground at the end
Rina8888 [55]

Answer:

Thus, the velocity at the time of strike is same as the velocity at the time of projection.

Explanation:

Let a projectile is projected vertically upwards with a speed of u and reaches to the maximum height H.

At maximum height , the speed is zero and then the projective comes back on the ground.

Use the third equation of motion

v^2 = u^2 + 2 g h \\\\0 = u^2 - 2 g H\\\\\u =\sqrt{2gH}

Now let the velocity at the time of strike is v'.

Use third equation of motion, here initial velocity is zero.  

v'^2 = 0 + 2 g H \\\\v = \sqrt{2gH}

Thus, the velocity at the time of strike is same as the velocity at the time of projection.

8 0
3 years ago
A paint brush is dropped from the top of a tall ladder and free falls to the ground. What changes, if any, would be observed of
muminat

Answer:

Explanation:

As the paint brush is dropped from the top of a tall ladder it started free falling

i.e. velocity of brush increases as it falls down due to the acceleration provided by gravity.

We know acceleration due to gravity is the attraction experienced by the object due to earth attraction

Value of acceleration due to gravity is constant i.e. 9.8\ m/s^2

Therefore the correct choice is

velocity is increasing and acceleration is constant

4 0
4 years ago
R=1m.<br> Vt=+- 8m/s<br> atot (tan<br> √3)
erica [24]

What What What What...... error

7 0
2 years ago
PLEASE HELP ASAP WILL GIVE BRAINLIEST
antiseptic1488 [7]

Answer: B



Im not sure, if i am right then mark as brainiest please (:



6 0
3 years ago
Read 2 more answers
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