1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
KIM [24]
3 years ago
5

Gwen is researching the effects of a small asteroid impact in an area that has started to regrow after being hit ten years ago.

She considers the event to be a long-term change because the species of plants that were present had to start completely over from seeds after all of the plants in the area were killed by the impact. What is the error in Gwen’s thinking?
Physics
2 answers:
velikii [3]3 years ago
5 0

Answer:

D) This is a short-term change, not a long-term change.

Explanation:

Bumek [7]3 years ago
3 0

Answer:

Gwen’s assumption of asteroid hit as long term change is incorrect. Asteroid hit is not a long term change, instead, it is a short term change.  

Explanation:

Examples of short term changes are drought, flood, volcanic eruption, etc. A short term change occurs quickly and can immediately affect organisms but it doesn’t become a reason for species extinction. The effects of a short term change don’t prevail over a long span of time.

Examples of long term changes are ice age, global warming, deforestation, etc. Unlike a short term change, it takes time but the consequences are far-reaching. It can lead to species extinction.

In this question, asteroid hit is a quick and unexpected hazard, unlike the slow long term environmental changes.

You might be interested in
How does the density of fluid affect the magnitude of buoyancy acting on an object immersed in it
Oksi-84 [34.3K]

Answer:

Explanation:

more the density , more will be the buoyant force acting on it , less the density less will be the buoyant force acting on it. This is why people float in dead sea and sink in other seas

5 0
3 years ago
(c) Another spring has a spring constant of 250 N/m.
vovikov84 [41]
It is E=something which leases another something equaling another something
5 0
3 years ago
A racecar experiences a centripetal acceleration of 36.0 m/s2 as it travels at a constant speed of 27.0 m/s along a circular arc
alexdok [17]

Answer:

20.25 m

Explanation:

  • <u>Centripetal acceleration </u>is given by; the square of the velocity, divided by the radius of the circular path.

That is;

         <em><u>ac = v²/r</u></em>

<em>         </em><em><u> Where; ac = acceleration, centripetal, m/s², v is the velocity, m/s and r is the  radius, m</u></em>

Therefore;

r = v²/ac

  = 27²/36

  = 20.25 m

Hence the radius is 20.25 meters

5 0
3 years ago
Read 2 more answers
A current carrying loop of wire lies flat on a table top. When viewed from above, the current moves around the loop in a counter
lora16 [44]

Answer:

D &B

Explanation:

Using Fleming right hand rule that States that if the fore-finger, middle finger and the thumb of left hand are stretched mutually perpendicular to each other, such that fore-finger points in the direction of magnetic field, the middle finger points in the direction of the motion of positive charge, then the thumb points to the direction of the force

5 0
3 years ago
A pendulum of length L=36.1 cm and mass m=168 g is released from rest when the cord makes an angle of 65.4 degrees with the vert
pychu [463]

(a) -0.211 m

At the beginning the mass is displaced such that the length of the pendulum is L = 36.1 cm and the angle with the vertical is

\theta=65.4^{\circ}

The projection of the length of the pendulum along the vertical direction is

L_y = L cos \theta = (36.1 cm)(cos 65.4^{\circ})=15.0 cm

the full length of the pendulum when the mass is at the lowest position is

L = 36.1 cm

So the y-displacement of the mass is

\Delta y = 15.0 cm - 36.1 cm = -21.1 cm = -0.211 m

(b) 0.347 J

The work done by gravity is equal to the decrease in gravitational potential energy of the mass, which is equal to

\Delta U = mg \Delta y

where we have

m = 168 g = 0.168 kg is the mass of the pendulum

g = 9.8 m/s^2 is the acceleration due to gravity

\Delta y = 0.211 m is the vertical displacement of the pendulum

So, the work done by gravity is

W=(0.168 kg)(9.8 m/s^2)(0.211 m)=0.347 J

And the sign is positive, since the force of gravity (downward) is in the same direction as the vertical displacement of the mass.

(c) Zero

The work done by a force is:

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement

\theta is the angle between the direction of the force and the displacement

In this situation, the tension in the string always points in a radial direction (towards the pivot of the pendulum), while the displacement of the mass is tangential (it follows a circular trajectory): this means that the tension and the displacement are always perpendicular to each other, so in the formula

\theta=90^{\circ}, cos \theta = 0

and so the work done is zero.

5 0
3 years ago
Other questions:
  • What is instantaneous speed
    10·1 answer
  • Which of the following is true about a rigid body in dynamic equilibrium? The body can have translational motion, but it cannot
    10·1 answer
  • An object's gravitational potential energy is NOT directly related to which of the following?
    9·2 answers
  • HELP PLEASE!<br>Can anyone help with any of these?
    12·1 answer
  • Frank does 2400J of work in climbing a set of stairs. If he does the work in 6
    8·1 answer
  • If the net force on an object is zero then the object has
    8·1 answer
  • Consider a car moving with a constant velocity of 90 m/s. What is it’s acceleration.
    8·2 answers
  • Is it true that acceleration occurs when there is a change in speed
    14·2 answers
  • Which of the following statements about lipids and carbohydrates is true?
    15·1 answer
  • What are the properties of glass in relation to microscopy?
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!