All categories

2 years ago

The quotient below is shown without the decimal point. Use number sense to place the decimal point correctly.

Mathematics

1 answer:

katrin2010 [14]2 years ago

5 0

Answer:

35.8

Step-by-step explanation:

$\frac{340.1}{9.5}$ = 358

We know that our answer can never be greater than 358 since the dividend

is 340.1 and the divisor is 9.5;

Also,

Both values are to one decimal places and we can use this to solve the problem;

9 can divide 340 in about 37 place with a remainder of 7,

So, it is appropriate to make the solution 35.8

You might be interested in

Evaluate each absolute value expression below | 2 | + | 4 | | − 3 | + | 5 | | − 7 | + | − 1 | − | 6 |

Bingel [31]

Answer:

Step-by-step explanation:

The absolute value symbols turn any negative inside of them to a positive, so your expression is ...

2 + 4·3 +5·7 +1 -6

= 2 +12 +35 +1 -6

= 44

4 0

3 years ago

A class survey in a large class for first-year college students asked, “About how many minutes do you study on a typical weeknig

Anika [276]

Answer: (110.22, 125.78)

Step-by-step explanation:

The confidence interval for the population mean is given by :-

$\mu\ \pm z_{\alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given : Sample size = 463

$\mu=118\text{ minutes}$

$\sigma=65\text{ minutes}$

Significance level : $\alpha=1-0.99=0.01$

Critical value : $z_{\alpha/2}=z_{0.005}=\pm2.576$

We assume that the population is normally distributed.

Now, the 90% confidence interval for the population mean will be :-

$118\ \pm\ 2.576\times\dfrac{65}{\sqrt{463}} \\\\\approx118\pm7.78=(118-7.78\ ,\ 118+7.78)=(110.22,\ 125.78)$

Hence, 99% confidence interval for the mean study time of all first-year students = (110.22, 125.78)

3 0

3 years ago

Tina bought 20 apples and bananas for her class. Apples cost $1.50 each. Bananas cost $1.25 each. Tina spent $28 in all. How man

babunello [35]

Tina bought 12 bananas and 8 apples

6 0

3 years ago

Suppose N has a geometric distribution with parameter p. Derive a closed-form expression for E(N | N <= k), k = 1,2,... Check

vfiekz [6]

Answer:

P(X= k) = (1-p)^k-1.p

Step-by-step explanation:

Given that the number of trials is

N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.

Given p = success,

1 - p = failure

Hence the distribution is described as: Pr ( FFFF.....FS)

Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p

Pr((X=k) = (1 - p)^ (k-1) .p

Since N<=k

Pr (X =k) = p(1-p)^k-1, k= 1,2,...k

0, elsewhere

If the probability is defined for Y, the number of failure before a success

Pr (Y= k) = p(1-p)^y......k= 0,1,2,3

0, elsewhere.

Given p= 0.2, k= 3,

P(X= 3) =( 0.2) × (1 - 0.2)²

P(X=3) = 0.128

3 0

2 years ago

3x^2+6x+3y^2-12y+54=0 is a ____.

alexira [117]

Answer:

radius 2

Step-by-step explanation:

8 0

2 years ago