Answer:
0.0064
Step-by-step explanation:
Answer:
0.6048
Step-by-step explanation:
Given the following :
Assume a normal distribution :
Mean (m) = 105
Standard deviation (sd) = 20
Find the probability that a randomly selected adult has an IQ between 88 and 122 .
Z = (x - m) / sd
For IQ score of 88:
Z = (88 - 105) / 20
Z = (-17) / 20
Z = - 0.85
For IQ score of 122:
Z = (122 - 105) / 20
Z = (17) / 20
Z = 0.85
P(-0.85<Z<0.85) = P(Z < 0.85) - P(Z < - 0.85)
P(-0.85<Z<0.85) = (0.8023 - 0.1977)
P(-0.85<Z<0.85) = 0.6048
Answer:
(6,-7)
Step-by-step explanation:
subtract them:
-8x - 5y = -13
-4x - 5y = 11
you get
-4x = -24
so x = 6
plug x into the second equation:
-24 - 5y = 11
-5y = 35
y = -7
so your solution is (6,-7).