Answer:
The common ratio r = 2.
Step-by-step explanation:
Now s2 = a1r and s4 = a1r^3 where a1 = first term and r = common ratio so
s4 / s2 = a1r^3 / a1r = r^2 = 32/8
r^2 = 4
r = 2.
It shoukd be A if im not mistaken
Answer:
Let the distance of school and house is x k m
Then time taken at speed 2.5 km\hr=
2.5
x
hr
And time taken at speed 4 km\hr=
4
x
hr
∴
2.5
x
−
4
x
=
60
12
⇒
10
4x−2.5x
=
5
1
⇒x=3 km
Then the distance of school and house is 3 k m
may this help you
