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3 years ago

Solve the inequality 5(x + 1) > 50

Mathematics

2 answers:

Korolek [52]3 years ago

7 0

Answer:

Step-by-step explanation:

Here you go mate

∴Use PEMDAS

Parenthesis,Exponent,multiplication,Division,Addition,Subtraction

Step 1

5(x+1)>50 Equation/Question

Step 2

5(x+1)>50 Remove parenthesis

5x+5>50

Step 3

5x+5>50 Subtract 5 from sides

5x>45

Step 4

5x>45 Divide sides by 5

Answer

x>9

Hope this helps

Ganezh [65]3 years ago

5 0

Answer:

Step-by-step explanation:

I can help

Step 1

5(x + 1) > 50 Simplifying

Step 2

5(x + 1) > 50 Remove the parenthesis by dividing both sides by 5

x+1>10

Step 3

x+1>10 Subtract 1 from both sides

x+1-1>10-1

Answer

x>9

Hope this helps

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A un paciente se le toma la temperatura a las 7 am, 9 am, 2 pm y a las 4 pm. La primera segunda y cuarta lecturas son de 66 grad

Gnesinka [82]

Answer:

Step-by-step explanation:

(Lo siento, español no es mi primero lingua, pero intentaré mi mejor :) )

La ecuación is (66 + 90 + x + 94)/4 = 86

Multiple los dos de los lado por 4.

66 + 90 + x + 94 = 344

Hace 66 + 90 + 94, y ponelos a la otro lado con sustracción.

X = 94

94 es la tercera lecture.

7 0

4 years ago

1 1/4 divided by 1 2/5

Degger [83]

Answer:

25/28

Step-by-step explanation:

1 1/4=5/4

1 2/5=7/5

------------

(5/4)/(7/5)

(5/4)(5/7)

25/28

7 0

3 years ago

Start with the number n = 54527. Divide n by 5 and round the result up to an integer. Keep repeating the division and rounding s

Elza [17]

Without rounding, I make it six. You could do it this way
54527/5^6 comes to a little over 3. That should be close enough. I'm going to check this by doing the divisions. I could let the computer do it, but I'd like to see if there's a pattern. There isn't and the correct answer is

6 <<<< divisions.

5 0

4 years ago

If 13cos theta -5=0 find sin theta +cos theta / sin theta -cos theta

Ivahew [28]

Step-by-step explanation:

We have to find the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0.

$\red{\frak{Given}} \begin{cases} & \sf {13\ cos \theta\ -\ 5\ =\ 0\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \big\lgroup Can\ also\ be\ written\ as \big\rgroup} \\ & \sf {cos \theta\ =\ {\footnotesize{\dfrac{5}{13}}}} \end{cases}$

Here, we're asked to find out the value of (sinθ + cosθ)/(sinθ - cosθ), when 13 cosθ - 5 = 0. In order to find the solution we're gonna use trigonometric ratios to find the value of sinθ and cosθ. Let us consider, a right angled triangle, say PQR.

Where,

PQ = Opposite side
QR = Adjacent side
RP = Hypotenuse
∠Q = 90°
∠C = θ

As we know that, 13 cosθ - 5 = 0 which is stated in the question. So, it can also be written as cosθ = 5/13. As per the cosine ratio, we know that,

$\rightarrow {\underline{\boxed{\red{\sf{cos \theta\ =\ \dfrac{Adjacent\ side}{Hypotenuse}}}}}}$

Since, we know that,

cosθ = 5/13
QR (Adjacent side) = 5
RP (Hypotenuse) = 13

So, we will find the PQ (Opposite side) in order to estimate the value of sinθ. So, by using the Pythagoras Theorem, we will find the PQ.

Therefore,

$\red \bigstar {\underline{\underline{\pmb{\sf{According\ to\ Question:-}}}}}$

$\rule{200}{3}$

$\sf \dashrightarrow {(PQ)^2\ +\ (QR)^2\ =\ (RP)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ (5)^2\ =\ (13)^2} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ +\ 25\ =\ 169} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 169\ -\ 25} \\ \\ \\ \sf \dashrightarrow {(PQ)^2\ =\ 144} \\ \\ \\ \sf \dashrightarrow {PQ\ =\ \sqrt{144}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{PQ\ (Opposite\ side)\ =\ 12}}}}_{\sf \blue{\tiny{Required\ value}}}}$

∴ Hence, the value of PQ (Opposite side) is 12. Now, in order to determine it's value, we will use the sine ratio.

$\rightarrow {\underline{\boxed{\red{\sf{sin \theta\ =\ \dfrac{Opposite\ side}{Hypotenuse}}}}}}$

Where,

Opposite side = 12
Hypotenuse = 13

Therefore,

$\sf \rightarrow {sin \theta\ =\ \dfrac{12}{13}}$

Now, we have the values of sinθ and cosθ, that are 12/13 and 5/13 respectively. Now, finally we will find out the value of the following.

$\rightarrow {\underline{\boxed{\red{\sf{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}}}}}}$

By substituting the values, we get,

$\rule{200}{3}$

$\sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\Big( \dfrac{12}{13}\ +\ \dfrac{5}{13} \Big)}{\Big( \dfrac{12}{13}\ -\ \dfrac{5}{13} \Big)}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ {\footnotesize{\dfrac{\dfrac{17}{13}}{\dfrac{7}{13}}}}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{13} \times \dfrac{13}{7}} \\ \\ \\ \sf \dashrightarrow {\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{\cancel{13}} \times \dfrac{\cancel{13}}{7}} \\ \\ \\ \dashrightarrow {\underbrace{\boxed{\pink{\frak{\dfrac{sin \theta\ +\ cos \theta}{sin \theta\ -\ cos \theta}\ =\ \dfrac{17}{7}}}}}_{\sf \blue{\tiny{Required\ value}}}}$

∴ Hence, the required answer is 17/7.

6 0

3 years ago

All the fudge machines at a chocolate factory work at the same rate. Six machines working simultaneously can complete a big orde

madreJ [45]

Answer:

11 hours

Step-by-step explanation:

The number of machines working in the factory = 6 machines

Decreasing it by a factor of 2 =

6 ÷ 2 = 3 machines.

Hence:

If 6 machines complete a big order = 22 hours

3 machines = x hours

Cross Multiply

6 machines × x hours = 22 hours × 3 machines

x hours = 22 hours × 3/6

= 66/6

x = 11 hours

Therefoee, it would take 11 hours to fill the order if the number of working machines decreased by factor of 2.

6 0

3 years ago