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Arte-miy333 [17]
3 years ago
10

Matter is made up of particle. Which of the following statement is true about these particle? A. A partical that make up soild d

o not move B. The partical that make up liquied do not move C The particals that makes up all matter D Only the parcicals that make up gaeses are constanlly in motion
Chemistry
1 answer:
Andrews [41]3 years ago
8 0

Answer: Answer A

Explanation: sorry if I'm wrong but I'm sharing what I know

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Identify the number and kinds of atoms present in a molecule of each compound. caffeine c8h10n4o2 iron iii sulfate fe2(so4)3
finlep [7]
This problem is very easy to answer. You simply have to look at the subscripts of each element of the compound.

1. For caffeine, which has a molecular formula of C₈H₁₀N₄O₂, it contains 8 atoms of Carbon, 10 atoms of Hydrogen, 4 atoms of Nitrogen and 2 atoms of Oxygen.

2. For Iron(III) Sulfate, which has a molecular formula of Fe₂(SO₄)₃, it contains 2 atoms of Iron, 3 atoms of Sulfur, and 12 atoms of Oxygen.
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4 years ago
4. Traditional bomb calorimetry can be used to find the energy content of food. Why is it
VladimirAG [237]

Answer:

B. it accounts for all the energy in the good even if some of its largely excreted by th body

3 0
2 years ago
Which compound is ionic?<br> 1. CaBr2 <br> 2. NO2<br> 3. CH4<br> 4. NBr3
NARA [144]
It is number 1. CaBr2
3 0
3 years ago
How fast is the speed of light?
Tpy6a [65]

The speed of light is 299,792,458 meters per second in vacuum.
It's somewhat slower in any material substance, and different in
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(That's 186,282.4  miles per second.)


7 0
3 years ago
Calculate the entropy change for the reaction: Fe2O3(s) +3C(s) -&gt; 2Fe(s) + 3CO(g)Entropy data:Fe2O3(s): 90 J/K molC(s): 5.7 J
Annette [7]

Explanation:

We are given: entropy of Fe2O3 = 90J/K.mol

: entropy of C = 5.7J/K.mol

: entropy of Fe = 27.2J/K.mol

: entropy of CO = 198J/K.mol

\begin{gathered} \Delta S\text{ = S}_{products}-S_{reactants} \\  \\ \text{       = \lparen3}\times198+2\times27.2)-(3\times5.7+90) \\  \\ \text{       = 541.3J/K.mol} \end{gathered}

Answer:

The correct answer is C.

5 0
1 year ago
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