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alekssr [168]
3 years ago
6

A photon has an energy of 2.93 × 10 to the power of -25 J. What is its frequency? What type of electromagnetic radiation is this

photon?
Chemistry
2 answers:
Svet_ta [14]3 years ago
6 0
You need to know the energy frequency relationship for photons, which is thanks to Max Planck:

Photon Energy = Planck constant x Frequency

Rarranged:
Photon Energy / Planck Constant = Frequency

Planck Constant = 6.63x10^-34

2.93x10^-25 / 6.63x10^-34 = Frequency

valkas [14]3 years ago
3 0

<u>Answer:</u> The radiation has a frequency of 4.43\times 10^{9}Hz and is a type of radio wave.

<u>Explanation:</u>

The equation given by Planck's follows:

E=h\nu

where,

E = energy of the light  = 2.93\times 10^{-25}J

h = Planck's constant  = 6.62\times 10^{-34}Js

\nu = frequency of light = ?

Putting values in above equation, we get:

2.93\times 10^{-25}J=6.62\times 10^{-34}Js\times \nu\\\\\nu=\frac{2.93\times 10^{-25}J}{6.62\times 10^{-34Js}}=4.43\times 10^{9}Hz

The relation between frequency and wavelength is given as:

\nu=\frac{c}{\lambda}

where,

c = the speed of light = 3\times 10^8m/s

\nu = frequency of radiation = 4.43\times 10^{8}s^{-1}

\lambda = wavelength of the radiation = ?

Putting values in above equation, we get:

4.43\times 10^{8}s^{-1}=\frac{3\times 10^8m/s}{\lambda}\\\\\lambda=\frac{3\times 10^8m/s}{4.43\times 10^8}s^{-1}}=0.677m

The radiation having wavelength 0.677 m belongs to radio waves.

Hence, the radiation has a frequency of 4.43\times 10^{9}Hz and is a type of radio wave.

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