Question

A photon has an energy of 2.93 × 10 to the power of -25 J. What is its frequency? What type of electromagnetic radiation is this photon?

Answer 1

You need to know the energy frequency relationship for photons, which is thanks to Max Planck:

Photon Energy = Planck constant x Frequency

Rarranged:
Photon Energy / Planck Constant = Frequency

Planck Constant = 6.63x10^-34

2.93x10^-25 / 6.63x10^-34 = Frequency

Answer 2

Answer: The radiation has a frequency of $4.43\times 10^{9}Hz$ and is a type of radio wave.

Explanation:

The equation given by Planck's follows:

$E=h\nu$

where,

E = energy of the light  = $2.93\times 10^{-25}J$

h = Planck's constant  = $6.62\times 10^{-34}Js$

$\nu$ = frequency of light = ?

Putting values in above equation, we get:

$2.93\times 10^{-25}J=6.62\times 10^{-34}Js\times \nu\\\\\nu=\frac{2.93\times 10^{-25}J}{6.62\times 10^{-34Js}}=4.43\times 10^{9}Hz$

The relation between frequency and wavelength is given as:

$\nu=\frac{c}{\lambda}$

where,

c = the speed of light = $3\times 10^8m/s$

$\nu$ = frequency of radiation = $4.43\times 10^{8}s^{-1}$

$\lambda$ = wavelength of the radiation = ?

Putting values in above equation, we get:

$4.43\times 10^{8}s^{-1}=\frac{3\times 10^8m/s}{\lambda}\\\\\lambda=\frac{3\times 10^8m/s}{4.43\times 10^8}s^{-1}}=0.677m$

The radiation having wavelength 0.677 m belongs to radio waves.

Hence, the radiation has a frequency of $4.43\times 10^{9}Hz$ and is a type of radio wave.