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3 years ago

Gaseous vapor observed when handling dry ice (solid co_2 2 ) physical or chemical

1 answer:

3 0

<span>Dry ice is frozen carbon dioxide. It is easy to assume that the fog surrounds dry ice is carbon dioxide returning to it's gaseous however, you can not see that process. The vapors you see is the water molecules in the air condensing as a result of the cooling or energy removal by the dry ice. When energy is removed from water molecules they become colder and move slower than water in a gaseous. Similar to clouds in the air, the water condenses into a form that you can see.</span>

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An important industrial route to extremely pure acetic acid is the reaction of methanol with carbon monoxide:

Nastasia [14]

The reaction has had a heat that is enthalpy of -22 kJ/mol. The exothermic process has been signaled by the negative sign.

The amount of energy that the system absorbs or releases to create the products is described as the heat of reaction.

The source of the reaction's heat is

H is equal to 3(413 Kj/mol) + 358 Kj/mol + 467 Kj/mol + 1070 Kj/mol = 3134 Kj/mol.

H prod equals 3(413 kj/mol) plus 347 kj/mol plus 358 kj/mol plus 467 kj/mol plus 745 kj/mol, or 3156 kj/mol.

H=3134 kj/mol - 3156 kj/mol = -22 Kj/mol

Negative findings point to an exothermic response.

A chemical process known as an exothermic reaction releases energy in the form of heat or light.

Learn more about exothermic reaction here-

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7 0

1 year ago

Suppose the gas resulting from the sublimation of 1.00 g carbon dioxide is collected over water at 25.0◦c into a 1.00 l containe

jeyben [28]

Answer:

0.55 atm

Explanation:

First of all, we need to calculate the number of moles corresponding to 1.00 g of carbon dioxide. This is given by

$n=\frac{m}{M_m}$

where

m = 1.00 g is the mass of the gas

Mm = 44.0 g/mol is the molar mass of the gas

Substituting,

$n=\frac{1.00 g}{44.0 g/mol}=0.0227 mol$

Now we can find the pressure of the gas by using the ideal gas law:

$pV=nRT$

where

p is the gas pressure

V = 1.00 L is the volume

n = 0.0227 mol is the number of moles

R = 0.082 L/(atm K mol) is the gas constant

T = 25.0 C + 273 = 298 K is the temperature of the gas

Solving the formula for p, we find

$p=\frac{nRT}{V}=\frac{(0.0227 mol)(0.082 L/(atm K mol))(298 K)}{1.00 L}=0.55 atm$

8 0

3 years ago

If nitrogen and hydrogen combine in a combustion reaction, what would the product of the reaction be?

kow [346]

Co2

Explanation:

CH4 (g) + 2 O2 (g) → CO2 (g) + 2 H2O (l)

4 0

3 years ago

Read 2 more answers

Name a possible product of this reaction in the presence of ether and AlCl3: methylbenzene + 1-chlorodecane.a. 1-methyl-2-decylb

Vikki [24]

Answer:

None of these

Explanation:

Friedel–Craft reaction is a reaction involves the attachment of substituents to the benzene ring.

Mechanism of the reaction of methylbenzene with 1-chlorodecane in the presence of ether and aluminum chloride :

Step -1 : Generation of stable carbocation.

Aluminium chloride acts as Lewis acid which removes the chloride ion from the alkyl halide forming carbocation. The primary carbocation thus formed gets rearranged to secondary primary carbocation which is more stable due to hyperconjugation.

Step-2: Attack of the ring to the carbocation

The pi electrons of the ring behave as a nucleophile and attacks the carbocation. Since, the group attached on the benzene is methyl (+R effect) , the attack is from the ortho and the para positions. Para product is more stable due to less steric hinderance.

The product formed is shown in mechanism does not mention in any of the options.

So, None of these is the answer