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2 years ago

Write the quadratic equation y = x2- 6x + 7 in vertex form

Mathematics

1 answer:

Sedbober [7]2 years ago

7 0

Answer:

y=(x-3)^2-2

Step-by-step explanation:

y=x^2-6x+7

or y=x^2-6x+9-9+7

or y=(x-3)^2-2

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Whoever can answer c please help me this is for a grade

Fofino [41]

pyramid A: 16 + $8\sqrt{5$

pyramid B: 400 + $8\sqrt{125$

pyramid A: 4 by 4= 16 cm.

with a height of 1 and length of 2, we use pythagorean theorem to find height of other surfaces to be square root of 5. area of triangle is 1/2 bh

square root of 5 multiplied by 4 and divided by 2 is 2 root 5

multiply this by 4 sides total for 8 root 5

Add the 8 root 5 to 16

To find pyramid B: use ratio of 25:1 and multiply 16 by 25 to find 400, and root 5 to 125

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2 years ago

I need help finding the answer to this question on edge.

Aliun [14]

Answer:

Step-by-step explanation:

We need to evaluate :-

$\rm\implies \displaystyle\rm\sum^4_n (-1)^n (3n + 2 )$

Here the $\Sigma$ is the sum operator . And here we need to find the sum from n = 1 to n = 4 . We can write it as ,

$\rm\implies (-1)^1 ( 3*1 +2) + (-1)^2 ( 3*2+2) + (-1)^3(3*3+2) + (-1)^4(3*4+2)$

Now we know that for odd powers of -1 , we get -1 and for even powers we get 1 . Therefore ,

$\rm\implies -1 ( 3 + 2 ) + 1 (6+2)+-1(9+2)+1(12+2)$

Now add the terms inside the brackets and then multiply it with the number outside the bracket . We will get ,

$\rm\implies -1 * 5 + 1 * 8 + -1*11 + 1*14 \\\\\rm\implies -5 + 8 - 11 + 14 \\\\\rm\implies\boxed{\quad 6 \quad}$

Hence the required answer is 6.

6 0

2 years ago

The problem has been started for you. 8 StartLongDivisionSymbol 468 EndLongDivisionSymbol minus 40 = 68. 68 minus 64 to get a re

stich3 [128]

Answer:

Step-by-step explanation:

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2 years ago

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Solve for x. Write both solutions, separated by a comma. 5x2 + 2x - 7 = 0

Sidana [21]

Answer:

uga buga

Step-by-step explanation:

dont know

7 0

3 years ago

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Please help me! I don't understand this! DUE TODAY

pishuonlain [190]

Answer: See the answers below.

The first equation that needs to be solve is: 10 = -16t^2 + 18
If you use the quadratic equation, you will get 0.707 seconds.

For the second equation, you need to solve 0 = -16t^2 + 18.
If you use the quadratic equation, you will get 1.061 seconds.

No, the rate of change is not constant because this is a quadratic equation.

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3 years ago