Answer:
with what 0-0 are youy okay?
Step-by-step explanation:
<u>Given</u>:
Given that FGH is a right triangle. The sine of angle F is 0.53.
We need to determine the cosine of angle H.
<u>Cosine of angle H:</u>
Given that the sine of angle F is 0.53
This can be written as,
Applying the trigonometric ratio, we have;
----- (1)
Now, we shall determine the value of cosine of angle H.
Let us apply the trigonometric ratio 
, we get;
----- (2)
Substituting the value from equation (1) in equation (2), we get;
Thus, the cosine of angle H is 0.53
Answer:
<u>I'll give the choices by the number below:</u>
- 1. 45 miles. Taken from the table at day 0.
- 2. 39 miles. Given for Miguel.
- 3. Jose's. His goal has a greater value 45 > 39.
- 4. 5 miles a day. Change per day as per table.
- 5. 6.5 miles a day. Given.
- 6. Miguel's. Comparing 6.5 > 5
Answer: 0=0 The input is an identity or it is true for all values
-3(2x+6)=-6x-18
(-3*2x)+(-3*6)=-6x-18
-6x+-18=-6x-18
0=0
Answer:answer is a (x+8)^2=86
Step-by-step explanation:
x+8=±√
86
2 Break down the problem into these 2 equations.
x+8=\sqrt{86}x+8=√
86
x+8=-\sqrt{86}x+8=−√
86
3 Solve the 1st equation: x+8=\sqrt{86}x+8=√
86
.
x=\sqrt{86}-8x=√
86
−8
4 Solve the 2nd equation: x+8=-\sqrt{86}x+8=−√
86
.
x=-\sqrt{86}-8x=−√
86
−8
5 Collect all solutions.
x=\sqrt{86}-8,-\sqrt{86}-8x=√
86
−8,−√
86
−8
x
2
+16x−22=0
2 Use the Quadratic Formula.
x=\frac{-16+2\sqrt{86}}{2},\frac{-16-2\sqrt{86}}{2}x=
2
−16+2√
86
,
2
−16−2√
86
3 Simplify solutions.
x=-8+\sqrt{86},-8-\sqrt{86}x=−8+√
86
,−8−√
86
