sorry wait please delete my answer I realized my mistake!
<span>The quadrilateral ABCD have vertices at points A(-6,4), B(-6,6), C(-2,6) and D(-4,4).
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<span>Translating 10 units down you get points A''(-6,-6), B''(-6,-4), C''(-2,-4) and D''(-4,-6).
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Translaitng <span>8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.
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</span><span>Answer: correct choice is B.
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Answer:
-123
Step-by-step explanation:
The remainder theorem says that when a polynomial is divided by a linear factor x - c (note the minus sign), the remainder is the value of the polynomial at x = c.
When a polynomial P(x) is divided by x - c, the remainder is P(c). In other words, to find the remainder, plug in c for x.
You're dividing by x + 4 which is the same thing as x - (-4) -- the role of c is being played by -4.
3(–4)^3 – (–4)^2 – 20(–4) + 5 = –123
M=30° because the right angle and 60 degree angle equal 150 and 180 (degrees in a triangle) minus 150 is 30
n=50° because 40 plus the right angle is 130 then the difference between that and 180 is 50 then n is the vertex angle of the one you found
t=98° because answer n plus the other part to the straight angle including the 112° angle is 68 then the total angle turns to 118 then the final angle turns to 62 via earlier reasoning, then because of another straight angle t=98
use the earlier reasoning to fine the other answers of
p=71°
q=39°
use the angle degrees formula to get Pentagon's maximum angles then use earlier resources
the final answers u should be able to figure out from there and u will never learn unless you do some yourself
Answer:
Step-by-step explanation:
So...
you would add -4 and -2 1/2 giving the total of -6 1/2.
All thats left is for you to graph it:)
(Please mark brainliest)
