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grin007 [14]
3 years ago
5

:)

Computers and Technology
1 answer:
Vilka [71]3 years ago
5 0

Answer:

A, system software

Explanation:

that is answer an interpreter is a type of system software

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0.0005 x 10⁻⁴ Farad = 0.000 000 05 Farad.
1 pF = 0.000 000 000 001 Farad

Divide them and get 50000 pF.
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Answer:

I think its plain text but I might be wrong

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when someone answers your questio correctly, you will see a red crown. Click on that and mark them the most brainiest

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def transfer(bank, log_in, userA, userB, amount): ''' In this function, you will try to make a transfer between two user account
laiz [17]

Answer:

def transfer(bank, log_in, userA, userB, amount): ''' In this function, you will try to make a transfer between two user accounts. bank is a dictionary where the key is the username and the value is the user's account balance. log_in is a dictionary where the key is the username and the value is the user's log-in status. amount is the amount to be transferred between user accounts (userA and userB). amount is always positive. What you will do: - Deduct the given amount from userA and add it to userB, which makes a transfer. - You should consider some following cases: - userA must be in the bank and his/her log-in status in log_in must be True. - userB must be in log_in, regardless of log-in status. userB can be absent in the bank. - No user can have a negative amount in their account. He/she must have a positive or zero balance. Return True if a transfer is made. For example:

Explanation:

i know this much

8 0
2 years ago
write a 2d array c program that can capture marks of 15 students and display the maximum mark, the sum and average​
bekas [8.4K]

Answer:

#include <stdio.h>  

int MaxMark(int* arr, int size) {

   int maxMark = 0;

   if (size > 0) {

       maxMark = arr[0];

   }

   for (int i = 0; i < size; i++) {

       if (arr[i] > maxMark) {

           maxMark = arr[i];

       }

   }

   return maxMark;

}

int SumMarks(int* arr, int size) {

   int sum = 0;

   for (int i = 0; i < size; i++) {

       sum += arr[i];

   }

   return sum;

}

float AvgMark(int* arr, int size) {

   int sum = SumMarks(arr, size);

   return (float)sum / size;

}

int main()

{

   int student0[] = { 7, 5, 6, 9 };

   int student1[] = { 3, 7, 7 };

   int student2[] = { 2, 8, 6, 1, 6 };

   int* marks[] = { student0, student1, student2 };

   int nrMarks[] = { 4, 3, 5 };

   int nrStudents = sizeof(marks) / sizeof(marks[0]);

   for (int student = 0; student < nrStudents; student++) {              

       printf("Student %d: max=%d, sum=%d, avg=%.1f\n",  

           student,

           MaxMark(marks[student], nrMarks[student]),

           SumMarks(marks[student], nrMarks[student]),

           AvgMark(marks[student], nrMarks[student]));

   }

   return 0;

}

Explanation:

Here is an example using a jagged array. Extend it to 15 students yourself. One weak spot is counting the number of marks, you have to keep it in sync with the array size. This is always a problem in C and would better be solved with a more dynamic data structure.

If you need the marks to be float, you can change the types.

3 0
2 years ago
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