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tamaranim1 [39]
3 years ago
7

PLEASE HELP! Which points lie in the second quadrant? Check all that apply?

Mathematics
1 answer:
nevsk [136]3 years ago
3 0

Answer:

is there picture?

Step-by-step explanation:

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HELP MEEE RNNNNNNNNNNNNN
dolphi86 [110]

As this rectangle has it's sides parallel to x axis and y axis

it is easy to find the length of it's sides by counting the number of blocks on each sides.

Let us first find co ordinates of all four points

we would calculate them left and right and up down direction from the origian ( the cross point of x and y axis )

A : it is 2 unit left 2 unit up ( -2 , +2 )

B is 5 unit right 2 unit up ( +5 ,+2)

C is 5 unit right 2 unit down ( +5,-2)

D is 2 unit left 2 unit down ( -2,-2)

Let us now find the distance AB : A is 2 unit left B is 5 unit right so length AB= 2+5 = 7

Let us now find distance AD : A is 2 unit up and D is 2 unit down

so length AD= 2+2= 4

Answer should be 7 x 4 units

5 0
3 years ago
Read 2 more answers
Please help! I don’t have much to offer except the crown icon thing and 15 points.
Goshia [24]
<h2><u>SOLUTION</u><u>:</u></h2>

x/9>12

x>12×9

x>108

This is your answer

8 0
3 years ago
Kolby decided he wanted to go to the amusement park. The amusement park charges $8.00 for entry and $1.40 for each ride.
Dmitry_Shevchenko [17]

Answer:

Part A:

1.40x+8.00=C

Part B:

1.40x+8=26

        -8   -8

1.40x=18

/1.40    /1.40

x=11 total rides

Step-by-step explanation:

An expression to represent this would be 1.40x+8.00=C (C is total cost).

If you had $26.00 you would first spend $8.00 on the entry leaving you with $18.00. Then you would divide the $18 by $1.40 for each ride to get 12.8... It doesn't make sense to go on a fraction of a ride so you just round down to 11 rides

8 0
2 years ago
Describe a real world situauationthat could be modled by dividing two rational numbers
Dima020 [189]
You have 10 slices of cake, you and your friends Jerry, George, Martha, and Jenny ( just an example ) eat 2 slices of cake. 
A more real life one would be:
You have 6 bills to pay off, then two more come in, you only pay off 4, 
( I hope this helped, I'm sorry if any of this is wrong:) )
7 0
3 years ago
A person's blood glucose level and diabetes are closely related. Let x be a random variable measured in milligrams of glucose pe
soldier1979 [14.2K]

Using the normal distribution, it is found that:

a) 0.8599 = 85.99% probability that x is more than 60.

b) 0.1788 = 17.88% probability that x is less than 110.

c) 0.6811 = 68.11% probability that x is between 60 and 110.

d) 0.0643 = 6.43% probability that x is greater than 125.

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.  
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

  • The mean is of 87, thus \mu = 87.
  • The standard deviation is of 25, thus \sigma = 25.

Item a:

This probability is <u>1 subtracted by the p-value of Z when X = 60</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{60 - 87}{25}

Z = -1.08

Z = -1.08 has a p-value of 0.1401.

1 - 0.1401 = 0.8599

0.8599 = 85.99% probability that x is more than 60.

Item b:

This probability is the <u>p-value of Z when X = 110</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 87}{25}

Z = 0.92

Z = 0.92 has a p-value of 0.8212.

1 - 0.8212 = 0.1788.

0.1788 = 17.88% probability that x is less than 110.

Item c:

This probability is the <u>p-value of Z when X = 110 subtracted by the p-value of Z when X = 60</u>.

From the previous two items, 0.8212 - 0.1401 = 0.6811.

0.6811 = 68.11% probability that x is between 60 and 110.

Item d:

This probability is <u>1 subtracted by the p-value of Z when X = 125</u>, thus:

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 87}{25}

Z = 1.52

Z = 1.52 has a p-value of 0.9357.

1 - 0.9357 = 0.0643.

0.0643 = 6.43% probability that x is greater than 125.

A similar problem is given at brainly.com/question/24863330

7 0
3 years ago
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