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3 years ago

What is the surface area of the three-dimensional figure formed by the net shown?

Mathematics

1 answer:

jarptica [38.1K]3 years ago

3 0

Answer:

336 cm²

Step-by-step explanation:

1 rectangle 24 cm by 12 cm

1 triangle with base 12 cm and height 8 cm (combining the two small triangles into 1 larger triangle)

SA = 24 cm * 12 cm + 12 cm * 8 cm / 2

SA = 288 cm² + 48 cm²

SA = 336 cm²

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myrzilka [38]

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4 years ago

X^4 = 24 Solve for x

Ganezh [65]

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so
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3 years ago

Find the sum (3x^2+5x-8)+(5x^2-13x-5)

deff fn [24]

Hello,
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4 years ago

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Step-by-step explanation:

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3 years ago

Point

ololo11 [35]

Your question is poorly formatted; However, the correct question is:

Point A ( 3 , 4 ) and point M (5.5,0) is the midpoint of point A and point B. Determine the coordinates of B

Answer:

The coordinates of B is (8,-4)

Step-by-step explanation:

Given

Point A ( 3 , 4 )

Point M (5.5,0)

Required

Determine B

Since, M is the midpoint;

We'll solve this question using the following formula;

$M(x,y) = (\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})$

Where $(x,y) = (5.5,0)$ and $(x_1,y_1) = (3,4)$

Substitute values for x, y, x1 and y1 in the above formula;

This gives

$(5.5,0) = (\frac{3 + x_2}{2},\frac{4 + y_2}{2})$

By direct comparison, we have

$5.5 = \frac{3 + x_2}{2}$ and $0 = \frac{4 + y_2}{2}$

Solving $5.5 = \frac{3 + x_2}{2}$

Multiply both sides by 2

$11 = 3 +x_2$

Subtract 3 from both sides

$11- 3 = x_2$

$x_2 = 8$

Solving $0 = \frac{4 + y_2}{2}$

Multiply both sides by 2

$0 = 4 + y_2$

Subtract 4 from both sides

$0 - 4 = y_2$

$y_2 = -4$

Hence;

The coordinates of B is (8,-4)

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3 years ago