The area of the shaded region is going to be the area of the rectangle minus the area of the square.
Area of a rectangle is L * W.
A = L * W
A = (x + 10)(2x + 5)
A = x(2x + 5) + 10(2x + 5)
A = 2x^2 + 5x + 20x + 50
A = 2x^2 + 25x + 50 .....this is the area of the rectangle
area of a square is : A = a^2...where a is one side
A = (x + 1)^2
A = (x + 1)(x + 1)
A = x(x + 1) + 1(x + 1)
A = x^2 + x + x + 1
A = x^2 + 2x + 1
now we subtract the area of the square from the area of the rectangle to get the area of the shaded region.
2x^2 + 25x + 50 - (x^2 + 2x + 1) =
2x^2 + 25x + 50 - x^2 - 2x - 1 =
x^2 + 23x + 49 <== the area of the shaded region
Answer:
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Step-by-step explanation:
Answer:
-8
Step-by-step explanation:
f(x) = 3x + 1
f(-3) = 3(-3) + 1
F(-3)=-9+1
f(-3)= -8
Problem: 4+x=15
- Subtract 4 from both sides
4+x-4=15-4
- Refine
x = 11
Answer:
yes
Step-by-step explanation:
well plug it in: y=6x -> y=6(3/9) and solve, yes if theres a slope of 1
